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Bess [88]
3 years ago
5

E how many different ways is it possible to answer an 8-question true/false quiz?

Mathematics
1 answer:
Otrada [13]3 years ago
5 0

Answer:

16

Step-by-step explanation:

8 questions

2 answers per question

8*2= 16

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If a square has a perimeter of 40 yards, what is the length of one side of the square?
zhannawk [14.2K]
10 yards because a square has 4 sides and all four sides are equal and so 40 divided by 4 equals 10
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Which of the following are properties of the graph of an odd monomial function? Select all that apply.
trapecia [35]

Answer:

1,4,5,7

Step-by-step explanation:

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3 years ago
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PLS I NEED HELP GUYS IM DESPERATE!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
goldenfox [79]

Answer:

3,4,5 because they only need one dice to be rolled while the rest need to dice to land perfectly

Step-by-step explanation:

4 0
3 years ago
8.
densk [106]

Camila's data set has the greatest interquartile range and the value of IQR = 8 option third is correct.

<h3>What is the range?</h3>

It is defined as the difference between the maximum value in the data set to the minimum value in the data set.

We have:

The amount of money in tips earned by four restaurant servers waiting on 10 tables is represented by the following data sets:

Alyssa {3, 6, 2, 8, 12, 14, 5, 7, 7, 8}

Bryant {9, 2, 7, 50, 0, 5, 2, 8, 6, 8}

Camila {1, 9, 10, 3, 0, 12, 10, 9, 8, 2}

Devon {4, 2, 8, 15, 20, 7, 5, 0, 6, 2}

The IQR for Alyssa:

IQR = Q3 - Q1

IQR = 8 - 5 = 3

The IQR for Bryant:

IQR = Q3 - Q1

IQR = 8 - 2 = 6

The IQR for Camila:

IQR = Q3 - Q1

IQR = 10 - 2 = 8

The IQR for Devon:

IQR = Q3 - Q1

IQR = 8 - 2 = 6

Thus, Camila's data set has the greatest interquartile range and the value of IQR = 8 option third is correct.

Learn more about the range here:

brainly.com/question/17553524

#SPJ1

8 0
2 years ago
You are working in a small, student-run company that sends out merchandise with university branding to alumni around the world.
topjm [15]

Answer:

The answer is "0.142466".

Step-by-step explanation:

Using the p formula for the proportion of nonconforming units through the subgrouping which can vary in sizes:

p =\frac{np}{n}\\\\

\bar{p}=\frac{\Sigma np}{\Sigma n}\\\\

Defects = \frac{5}{100} \times 50 \\\\

p = \frac{5}{100} \times \frac{50}{50}=0.05\\\\

It calculates the controls limits through the p-chart that is:

UCL_{p},LCL_{p}=\bar{p} \pm \sqrt{\frac{\bar{p}(1-\bar{p})}{\bar{n}}}\\\\

So, the upper control limits:

= 0.05 + 3 \times \sqrt{(\frac{0.05\times(1-0.05)}{50})} \\\\= 0.142466

7 0
3 years ago
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