Distance traveled in 3 hrs was (speed in mph)(3 hrs)
Then s(3 hrs) + 12 mi = 132 mi.
Therefore, 3s = 120, and s = 120 miles / 3 hrs = 40 mph (answer)
Answer:
change the equation into one variable.
2 y equals 10 + x
y equals 5 + x by 2
now put that into the second equation
-3x + b parentheses 5 + x / 2 equals 11
-3x+b(5+ x/2)
-3x + b5 + bx/2 = 11
The given above may be modeled by the arithmetic sequence with initial value (I) 2200 and common difference (d) of 70. The number of applicants every year can be written by the equation,
at = a1 + (n - 1) x d
From the given above, n is equal to 4. This corresponds to the term which is 3 years from now.
at = 2200 + (4 - 1) x 70 = 2410
Thus, the enrollment capacity would be 2410 students.
General Idea:
If we have a quadratic function of the form f(x)=ax^{2} +bx+c , then the function will attain its maximum value only if a < 0 & its maximum value will be at x=-\frac{b}{2a} .
Applying the concept:
The height h is modeled by h = −16t^2 + vt + c, where v is the initial velocity, and c is the beginning height of the firecracker above the ground. The firecracker is placed on the roof of a building of height 15 feet and is fired at an initial velocity of 100 feet per second. Substituting 15 for c and 100 for v, we get the function as
.
Comparing the function f(x)=ax^{2} +bx+c with the given function
, we get
,
and
.
The maximum height of the soccer ball will occur at t=\frac{-b}{2a}=\frac{-100}{2(-16)} = \frac{-100}{-32}=3.125 seconds
The maximum height is found by substituting
in the function as below:

Conclusion:
<u>Yes !</u> The firecracker reaches a height of 100 feet before it bursts.
Answer:
Weight of dog: 34 pounds,
Weight of cat: 12 pounds.
Step-by-step explanation:
Let d represent weight of dog and c represent weight of cat.
We have been given that a dog weighs two pounds less than three times the weight of a cat.
3 times weight of cat: 
We can represent the given information in an equation as:

We are also told that the dog also weights twenty-two more pounds than the cat. We can represent the given information in an equation as:

Equate both equations:






Therefore, the weight of cat is 12 pounds.
Substitute
in equation (2)



Therefore, the weight of dog is 34 pounds.