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Misha Larkins [42]
3 years ago
10

What is the value of x? x = [? ]° Enter

Mathematics
1 answer:
svetlana [45]3 years ago
5 0
180/3 = 60 and I believe x is 60/2 = 30
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95i is a root of f(x)=x^2 +9025. find the other roots of f(x)
Alex_Xolod [135]

Answer:

Other root is -95i

Step-by-step explanation:

Here, Nature of roots of f(x) is imaginary roots.

Therefore, Roots are conjugate of each other.

Conjugate of x + yi is x - yi.

we get conjugate of 95i as -95i

Verification shows....

(x-95)(x+95i)=0

{x }^{2}  -  {95}^{2}  {i}^{2}  = 0 \\  {x }^{2}   + {95}^{2} = 0  \\ {x }^{2}   + 9025= 0   \\ f(x) = 0

this, roots are -95i and 95i

5 0
4 years ago
Pleaseee help, question what is the sum of 4x^2 + 2x - 5 and 7x^2 - 5x + 2
Nataliya [291]

Simplification of polynomials.

Polynomials <em>are</em> mathematical expressions made up of many terms.<em>To</em> simplify a polynomial <em>the most, you must collect all</em><em> </em>like terms <em>and rearrange them from highest to lowest power.</em>

<h3>4x² + 2x -5 + 7x² - 5x+2</h3><h3>4x² + 2x -3 + 7x² - 5x+2</h3><h3>11x² + 2x - 3 - 5x</h3><h3>11x² - 3x - 3 ====> Option "A"</h3>
6 0
1 year ago
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I ONLY need help with the tables ONLY! I’LL GIVE BRAINLIEST FOR THE RIGHT ANSWER?! I please include what you did for both tables
neonofarm [45]

Answer:

The first table.

Step-by-step explanation:

Every single time, the x is being multiplied by 3 to get the y, and that means its proportional. Also, the second one is for sure NOT proportional

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3 years ago
Evaluate (4p)3 when p = (-1)
Leona [35]

Answer:

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plug in -1 into the equation which is going to be (4*-1)3

you multiply what is in the parenthesis first and after is going to be (-4)3

lastly your going to multiply -4*3 and it is going to equal to -12.

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makvit [3.9K]

I cant give you the answer without the picture but I can tell you how to solve it.

if all the sides are the same length just multiply one of the numbers by the sides, for example, a rubics cube is 9 cm on each side. 9*6=54, so the answer would be 54 cm

6 0
3 years ago
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