I need help with questions 9
1 answer:
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So... our numbers... let's say the first one is hmmm "a"
so the second and subsequent are
a
a+1
a+2
a+3
a+4
there, 5 consecutive whole numbers or integers for that matter
now, we know the sum of the square of the first three,
is the same as the sum of the square of the last two
so
do a binomial theorem expansion on those, solve for "a"
so the second and subsequent are
a
a+1
a+2
a+3
a+4
there, 5 consecutive whole numbers or integers for that matter
now, we know the sum of the square of the first three,
is the same as the sum of the square of the last two
so
do a binomial theorem expansion on those, solve for "a"
Option D: is the function
Explanation:
Let the general form of quadratic equation be
The function passes through the intercepts and
and also passes though the point
Substituting the points ,
and
in the equation
, we get,
-----------(1)
----------(2)
-----------(3)
Subtracting (1) and (2), we get,
-----------(4)
Subtracting (2) and (3), we get,
------------(5)
Multiplying equation (4) by 5 and equation (5) by 4, to cancel the term b when adding, we get,
Thus, the value of a is
Substituting in equation (4), we get,
Thus, the value of b is
Now, substituting the value of a and b in equation (1), we have,
Thus, the value of c is
Now, substituting the value of a,b and c in the general formula , we get,
Taking out the common term as -2 we get,
Factoring , we get,
Thus, the function is