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ser-zykov [4K]
3 years ago
10

Help me i nee helpppppp

Mathematics
2 answers:
Mama L [17]3 years ago
7 0

Answer:

0.03

3 tenths

(3 x 1/100) + (3 x 1/100)

Step-by-step explanation:

3 tenths = .3

.3 > .003

(3 x 1/100) = .3

.3 + .3 = .6

.6 > .3

jek_recluse [69]3 years ago
7 0

Answer:

3 tenths, (3 x (1/100)) + (3 x (1/100)), .03

Step-by-step explanation:

The first option would equal \frac{6}{100} which can be simplified to \frac{3}{50} or .06

  • (3)(\frac{1}{100}) is 3/100
  • 3/100 + 3/100 = 6/100
  • it is that because when adding fractions you want the denominators (which is the number 100 in this problem) to be the same
  • when the denominators are the same, you can the numerators like you're doing regular addition (3 + 3 = 6)

3 tenths is .3

  • First, let's go over the places in decimals
  • .1 would be one tenth, because it is in the tenths place
  • .01 would be one hundreths because it is in the hundreths place
  • .001 would be one thousandth because it is in the thousandths place
  • it goes on from there
  • it's the opposite if the number was in front of the decimal, like 10 is ten, 100 is one hundred, 1000 is one thousand. there is no "oneths" place in decimals

.03 is three hundreths (see above info if confused)

- the further away a number is on the right side of the decimal, the smaller it is. for example, .04 is bigger than .004, or .05 is bigger than .006 . the closer the decimal is to 1.0, the bigger it is.

now let's put these in order (biggest to smallest)

1) .3

2) .06

3) .03

that means the correct order would be...

3 tenths, (3 x (1/100)) + (3 x (1/100)), .03

please comment or message me if you are still confused!

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A toy rocket is launched from a platform that is 48 ft high. The rocket height above the ground is modeled by h=-16t^2+32t+48. a
Komok [63]

Answer:

a) 64 feet

b)  3 seconds

Step-by-step explanation:

a)

The maximum height of h=h(t) can be bound by finding the y-coordinate of the vertex of y=-16x^2+32x+48.

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y=-16(1)^2+32(1)+48

y=-16+32+48

y=16+48

y=64

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b)

When the rocket hit's the ground the height that the rocket will be from the ground is 0 ft.

So we are trying to find the second t such that:

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I'm going to divide both sides by -16:

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The second equation can be solved by subtracting 1 on both sides: t=-1.

So when t=3 seconds, is when the rocket has hit the ground.

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