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Helga [31]
3 years ago
11

Match these items.

Physics
2 answers:
viva [34]3 years ago
6 0
-- 'Ca' (Calcium) is an element.
-- The proton has a positive charge.
-- Nuclear fusion results in the synthesis of atoms of new elements.
-- H₂O (water) is a chemical compound. 
-- Nuclear fission is a decay of the nucleus.
-- The atomic number of an element is the number of protons 
      in each atom of it.
-- I suppose you're using the Greek letter  <span>η  ('eta', not 'nu') 
      to represent the neutron.
-- I suppose you're using ' e ' to represent the electron.
</span>
maw [93]3 years ago
3 0

Explanation:

1. Ca  → element

Ca is a symbol of calcium element categorize as alkali earth metal.

2. H_2O  → compound

Compound is a substance made up of two more than two different elements.

3. Nuclear decay  → fission

Fission is defined as process in which heavier unstable nucleus divide itself into two or more smaller stable nuclei with release of large amount of energy.

4. Nuclear synthesis  → fusion

Fusion is defined as process in which two or more nuclei combines together to form an larger nucleus with release of large amount energy.

5. η  → neutron

One of the subatomic particle of an atom located in the nucleus of an atom with no electrical charge.

6. Positive charge  → proton

One of the subatomic particle of an atom located in the nucleus of an atom with positive electrical charge.

7. e  → electron

One of the subatomic particle of an atom located inside an atom and outside the nucleus of an atom with negative electrical charge.

8. Number of protons in nucleus → atomic number

Atomic number of an atom is equal to the total number of protons present in the nucleus if the an atom.

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Attention

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Which of these is not a type of force?
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6 0
3 years ago
Read 2 more answers
A high-speed flywheel in a motor is spinning at 450 rpm when a power failure suddenly occurs. The flywheel has mass 40.0 kg and
alexira [117]

Answer:

A) \omega_f=17.503\ rad.s^{-1}

B) t=55.6822\ s

C) \theta=1312\ rad

Explanation:

Given:

  • mass of flywheel, m=40\ kg
  • diameter of flywheel, d=0.72\ m
  • rotational speed of flywheel, N_i=450\ rpm \Rightarrow \omega_i=\frac{450\times 2\pi}{60} =15\pi\ rad.s^{-1}
  • duration for which the power is off, t_0=35\ s
  • no. of revolutions made during the power is off, \theta=180\times 2\pi=360\pi\ rad

<u>Using equation of motion:</u>

\theta=\omega_i.t+\frac{1}{2} \alpha.t^2

360\pi=15\pi\times 35+\frac{1}{2} \times \alpha\times35^2

\alpha=-0.8463\ rad.s^{-2}

Negative sign denotes deceleration.

A)

Now using the equation:

\omega_f=\omega_i+\alpha.t

\omega_f=15\pi-0.8463\times 35

\omega_f=17.503\ rad.s^{-1} is the angular velocity of the flywheel when the power comes back.

B)

Here:

\omega_f=0\ rad.s^{-1}

Now using the equation:

\omega_f=\omega_i+\alpha.t

0=15\pi-0.8463\times t

t=55.6822\ s is the time after which the flywheel stops.

C)

Using the equation of motion:

\theta=\omega_i.t+\frac{1}{2} \alpha.t^2

\theta=15\pi\times 55.68225-0.5\times 0.8463\times 55.68225^2

\theta=1312\ rad revolutions are made before stopping.

3 0
3 years ago
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