3x² 2x+4 =0 What's the number of Solutions? 3x-2x+4=0 how many solutions???

Wich of the following best describes the expression 4(y+6)

algol [13]

Answer: 4y + 24

Explanation:

3 0

3 years ago

If the original quantity is 14 and the new quantity is 22, which of these is the best estimate for the percent of change?

julsineya [31]

D 22-14=8 14-7=7 7 of 14=50% so i think that’s the best estimate

8 0

2 years ago

99 POINTS, NEED HELP WITH ALGEBRA

Tanya [424]

1 is in picture above.

2.

$average \: rate = \frac{f(4) - f(1)}{4 - ( - 1)} = \frac{5}{4 - ( - 1)} = 1$

3. In the picture...

4. In the picture...

5. Parts A and B are true.

6.

$average \: rate = \frac{f(0) - f( - 10)}{0 - ( - 10)} = \frac{( - 6) - 184}{0 - ( - 10)} = \frac{ - 190}{10} = - 19$

7. The axis symmetry equation of

$y = a {x}^{2} + bx + c$

is

$x = \frac{ - b}{2a}$

So it would be x=-3/4

8.

$y = {(x - 6)}^{2} + 10$

T=(6, 10) vertex coordinates...

4 0

3 years ago

Read 2 more answers

Draw and upload a dot plot to represent the following data.

ivann1987 [24]

Answer:

a

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

Social Sciences Alcohol Abstinence The Harvard School of Public Health completed a study on alcohol consumption on college campu

Scilla [17]

Answer:

a) There is a 6.69% probability that a randomly selected female student abstains from alcohol.

b) If a randomly selected female student abstains from alcohol, there is a 82.87% probability that she attends a coeducational college.

Step-by-step explanation:

This is a probability problem:

We have these following probabilities:

-20.7% of a woman attending an all-women college abstaining from alcohol.

-6% of a woman attending a coeducational college abstaining from alcohol.

-4.7% of a woman attending an all-women college

- 100%-4.7% = 95.3% of a woman attending a coeducational college.

(a) What is the probability that a randomly selected female student abstains from alcohol?

$P = P_{1} + P_{2}$

$P_{1}$ is the probability of a woman attending an all-women college being chosen and abstaining from alcohol. There is a 0.047 probability of a woman attending an all-women college being chosen and a 0.207 probability that she abstain from alcohol. So:

$P_{1} = 0.047*0.207 = 0.009729$

$P_{2}$ is the probability of a woman attending a coeducational college being chosen and abstaining from alcohol. There is a 0.953 probability of a woman attending a coeducational college being chosen and a 0.06 probability that she abstain from alcohol. So:

$P_{2} = 0.953*0.06 = 0.05718$

So, the probability of a randomly selected female student abstaining from alcohol is:

$P = P_{1} + P_{2} = 0.009729 + 0.05718 = 0.0669$

There is a 6.69% probability that a randomly selected female student abstains from alcohol.

(b) If a randomly selected female student abstains from alcohol, what is the probability she attends a coedücational colege?

This can be formulated as the following problem:

What is the probability of B happening, knowing that A has happened.

Here:

What is the probability of a woman attending a coeducational college, knowing that she abstains from alcohol.

It can be calculated by the following formula:

$P = \frac{P(B).P(A/B)}{P(A)}$

Where P(B) is the probability of B happening, P(A/B) is the probability of A happening knowing that B happened and P(A) is the probability of A happening.

We have the following probabilities:

$P(B)$ is the probability of a woman from a coeducational college being chosen. So $P(B) = 0.953$

$P(A/B)$ is the probability of a woman abstaining from alcohol, given that she attends a coeducational college. So $P(A/B) = 0.06$

$P(A)$ is the probability of a woman abstaining from alcohol. From a), $P(A) = 0.0669$

So, the probability that a randomly selected female student attends a coeducational college, given that she abstains from alcohol is:

$P = \frac{P(B).P(A/B)}{P(A)} = \frac{(0.953)*(0.06)}{(0.0669)} = 0.8287$

If a randomly selected female student abstains from alcohol, there is a 82.87% probability that she attends a coeducational college.

4 0

3 years ago