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trapecia [35]
3 years ago
6

Whats the area of the shaded regions (show work)

Mathematics
1 answer:
d1i1m1o1n [39]3 years ago
7 0

You need to show the pictures for us to answer.

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What is eight g plus ten equals thirty five plus three g
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8g+10=35+3g You need to find what number g is, just plug in random numbers till both sides are equal

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Right to explain how this digit 6 changes value in number 666, 666, 666
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To a higher number the six changes value in this number above
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Por que razón los números fraccionarios y decimales no tienen un sucesor y un antecesor​
stepan [7]

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Step-by-step explanation:

3 0
2 years ago
Find the area of the right triangle △DEF with the points D (0, 0), E (1, 1), and F.
Tems11 [23]

Answer:

The area of the triangle is  \sqrt{3}

Step-by-step explanation:

Given:

Coordinates D (0, 0), E (1, 1)

Angle  ∠DEF = 60°

△DEF is a Right triangle

To Find:

The area of the triangle

Solution:

The area of the triangle is  = \frac{1}{2}(base \times height)

Here the base is Distance between D and E

calculation the distance using the distance formula, we get

DE  = \sqrt{(0-1)^2 + (0-1)^2}

DE =\sqrt{(-1) ^2 + (-1)^2

DE = \sqrt{1+1}

DE = \sqrt{2}

Base = \sqrt{2}

Height is DF

DF =tan(60^{\circ}) \times DE

DF = \sqrt{3} \times DE

DF = \sqrt{3} \times\sqrt{2}

Now, the area of the triangle is

= \frac{1}{2}({\sqrt{2})(\sqrt{3} \times \sqrt{2})

=\frac{1}{2}({\sqrt{2})(\sqrt{3} \sqrt{2})

=\frac{1}{2}(2\sqrt{3} )

=\sqrt{3}

6 0
3 years ago
How do you convert from a radical expression to a rational exponent?
Murljashka [212]
 The denominator of the raised fraction is what goes on the outside of the square root. So if you had 2 raised to 1/3, you'd put the 3 raised outside to the left of the radical and the 2 inside. They give the same answer, so if you know one, you can always play with the other until you get the same answer. My teacher told us in Calculus a funny/weird way to remember it is the "bottom (of the raised fraction) goes in the crack (of the radical)." Does this help??
5 0
3 years ago
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