Answer:
No positive value of n
Step-by-step explanation:
we have to find out for how many positive values of n are both
our-digit integers
Let us consider first cube
we get 4digit lowest number is 1000 and it has cube root as 10.
Thus 10 is the least integer which satisfies four digits for cube.
The highest integer is 9999 and it has cube root as 21.54
or 21 the highest integer.
Considering 3^n we get,
3^10 is having 5 digits and also 3^21
Thus there is no positive value of n which satisfy that both n cube and 3 power n are four digits.
Step-by-step explanation:
you don't show us the choices.
anyway, the real graph must be similar to the one you are showing, as it goes to - and + infinity for x = 2.
because the denominator "x-2" will be 0 for x = 2.
but the horizontal limits are both y = +3 (and not 0).
because (3x-2)/(x-2) goes more and more to 3/1 the larger (or smaller in the - direction) x gets.
If you divide 18 and 6 you will get three so three times 1254 equals 3,762 card that he saw
Answer:
Step-by-step explanation:
1. 9x^5
2. 9x^6
3. 27x^5
4. 27x^6
Answer:
6
Step-by-step explanation:
do you want an explanation?
btw, plz brainliest :)