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vesna_86 [32]
3 years ago
13

I don't understand I need help​

Mathematics
2 answers:
solong [7]3 years ago
8 0

Answer:

I think A

Step-by-step explanation:

because the side lengths should be the same and going down the middle.

if I am wrong plz tell me

prohojiy [21]3 years ago
7 0
Using Pythagorean theorem I got the answer 127.3ft the letter b
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What is cos theta when sin theta = sqrt 2/3
Fittoniya [83]

<u>Answer:</u>

Value of cosθ is ±√7/3 .

<u>Step-by-step explanation:</u>

According to the Question , value of :

\red{\implies sin\theta = \dfrac{\sqrt2}{3}}

And , we know the identity of sine and cosine as ,

\boxed{\pink{\sf\implies sin^2\theta + cos^2\theta = 1} }

<u>Using</u><u> </u><u>,</u><u> </u><u>this</u><u> </u><u>ident</u><u>ity</u><u> </u><u>we</u><u> </u><u>have</u><u> </u><u>;</u><u> </u>

\implies sin^2\theta + cos^2\theta = 1 \\\\\implies \bigg( \dfrac{\sqrt2}{3}\bigg)^2 + cos^2\theta = 1 \\\\\implies \dfrac{2}{9} + cos^2\theta = 1 \\\\\implies cos^2\theta = 1 - \dfrac{2}{9} \\\\\implies cos^2\theta = \dfrac{9-2}{9} \\\\\implies cos\theta = \sqrt{\dfrac{7}{9}} \\\\\underline{\boxed{\blue{\bf \implies cos\theta = \pm \dfrac{\sqrt 7 }{3}}}}

Now , here since θ is in 2nd quadrant and in 2nd quadrant cos is negative . Hence ,the value of cos will be :

\boxed{\orange{\bf \implies cos\theta =-\dfrac{\sqrt7}{3}}}

3 0
3 years ago
HELP I NEED HELP ASAP<br><br> FIND THE SLOPE AND Y-INTERCEPT OF THE TABLE.
Murljashka [212]
I don’t know about the slope but the Y-Intercept is just the Y.
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3 years ago
How to find out the independent variable and dependent variable from a graph?
I am Lyosha [343]

Answer:

The Axes. The independent variable belongs on the x-axis the(horizontal line) of the graph and the dependent variable belongs on the y-axis the (vertical line)

6 0
3 years ago
I need help!!!!!
Elanso [62]

Answer:

1. 75% of 10 liters of milk = 0.75 * 10 liters of milk = 7.5 liters of milk

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5 0
3 years ago
Read 2 more answers
2x – y=8
emmasim [6.3K]

Answer:

the answer is D no solution

5 0
3 years ago
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