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3 years ago

I don't understand I need help

Mathematics

2 answers:

solong [7]3 years ago

8 0

Answer:

I think A

Step-by-step explanation:

because the side lengths should be the same and going down the middle.

if I am wrong plz tell me

prohojiy [21]3 years ago

7 0

Using Pythagorean theorem I got the answer 127.3ft the letter b

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An agriculture researcher wants to test the effect of nine soil additives by adding four at a time to different rows of the

Dafna11 [192]

Answer:

126

Step-by-step explanation:

Hope it helped :)

3 0

3 years ago

1.)<br> What is the solution to the system of equations below?<br> y = 2x + 8<br> 3(-2x + y) = 19

-BARSIC- [3]

Answer:

y = 2x + 8

6x + 3y = 19

6x + 3(2x + 8) = 19

6x + 6x + 24 = 19

12x = -5

x = -5/12

y = 2(-5/12) + 8

y = -5/6 + 48/6

y = 43/6

3 0

3 years ago

Shade the model to show the decimal 0.542 using 100 grid and 10 grid

kherson [118]

0.542=0.500 + 0.040+0.002

= $\frac{5}{10} + \frac{4}{100} +\frac{2}{1000}$

=5 tenth + 4 hundredths + two thousandths

One tenth = $\frac{1}{10}$

One Hundredth= $\frac{1}{100}$

One thousandth= $\frac{1}{1000}$

8 0

3 years ago

Read 2 more answers

The graph of an absolute value function opens down and has a vertex of (-3,0).

dsp73

I wrote the domain and range in interval notation, not sure if that’s how you’re asked to do it. This is how I was taught to state the domain/range of a graph.

3 0

3 years ago

Read 2 more answers

For a certain river, suppose the drought length Y is the number of consecutive time intervals in which the water supply remains

AnnZ [28]

Answer:

a) There is a 9% probability that a drought lasts exactly 3 intervals.

There is an 85.5% probability that a drought lasts at most 3 intervals.

b)There is a 14.5% probability that the length of a drought exceeds its mean value by at least one standard deviation

Step-by-step explanation:

The geometric distribution is the number of failures expected before you get a success in a series of Bernoulli trials.

It has the following probability density formula:

$f(x) = (1-p)^{x}p$

In which p is the probability of a success.

The mean of the geometric distribution is given by the following formula:

$\mu = \frac{1-p}{p}$

The standard deviation of the geometric distribution is given by the following formula:

$\sigma = \sqrt{\frac{1-p}{p^{2}}$

In this problem, we have that:

$p = 0.383$

$\mu = \frac{1-p}{p} = \frac{1-0.383}{0.383} = 1.61$

$\sigma = \sqrt{\frac{1-p}{p^{2}}} = \sqrt{\frac{1-0.383}{(0.383)^{2}}} = 2.05$

(a) What is the probability that a drought lasts exactly 3 intervals?

This is $f(3)$

$f(x) = (1-p)^{x}p$

$f(3) = (1-0.383)^{3}*(0.383)$

$f(3) = 0.09$

There is a 9% probability that a drought lasts exactly 3 intervals.

At most 3 intervals?

This is $P = f(0) + f(1) + f(2) + f(3)$

$f(x) = (1-p)^{x}p$

$f(0) = (1-0.383)^{0}*(0.383) = 0.383$

$f(1) = (1-0.383)^{1}*(0.383) = 0.236$

$f(2) = (1-0.383)^{2}*(0.383) = 0.146$

Previously in this exercise, we found that $f(3) = 0.09$

$P = f(0) + f(1) + f(2) + f(3) = 0.383 + 0.236 + 0.146 + 0.09 = 0.855$

There is an 85.5% probability that a drought lasts at most 3 intervals.

(b) What is the probability that the length of a drought exceeds its mean value by at least one standard deviation?

This is $P(X \geq \mu+\sigma) = P(X \geq 1.61 + 2.05) = P(X \geq 3.66) = P(X \geq 4)$ .

We are working with discrete data, so 3.66 is rounded up to 4.

Either a drought lasts at least four months, or it lasts at most thee. In a), we found that the probability that it lasts at most 3 months is 0.855. The sum of these probabilities is decimal 1. So:

$P(X \leq 3) + P(X \geq 4) = 1$

$0.855 + P(X \geq 4) = 1$

$P(X \geq 4) = 0.145$

There is a 14.5% probability that the length of a drought exceeds its mean value by at least one standard deviation

8 0

4 years ago

I don't understand I need help​

I don't understand I need help