1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
ioda
3 years ago
5

Identify the limiting reactant when 1.22 g of O2 reacts with 1.05 g H2 to produce water.

Chemistry
1 answer:
kupik [55]3 years ago
4 0
The reaction between oxygen, O2, and hydrogen, H2, to produce water can be expressed as,

                    2H2 + O2 --> 2H2O

The masses of each of the reactants are calculated below.

          2H2 = 4(1.01 g) = 4.04 g
          O2 = 2(16 g) = 32 g

Given 1.22 grams of oxygen, we determine the mass of hydrogen needed.
        (1.22 g O2)(4.04 g H2 / 32 g O2) = 0.154 g of O2

Since there are 1.05 grams of O2 then, the limiting reactant is 1.22 grams of oxygen.


<em>Answer: 1.22 g of oxygen</em>
You might be interested in
100 POINTS!!
elena55 [62]

Answer:

The correct matching of the air mass and the letters in the word bank are given as follows;

1. Warm and humid                   ↔       D

2. Extremely cold and dry        ↔       B

3. Cold and dry                         ↔       A

4. Cold and humid                    ↔       C

5. Warm and dry                       ↔        E

Where;

A Represents continental polar

B Represents Artic

C Represents Maritime Polar

D Represents Maritime Tropical

E Represents Continental Tropical

Explanation:

A. A continental polar is one that can be described as a cold and dry climate as the region is located at a further away from the oceanic water bodies that add humidity to the climate

B. The regions of the Artic and the Antarctic have very limited amount of precipitation every year because the air is very cold as well as dry

C. A polar climate is a cold climate region, while a maritime climate is humid.

Therefore, the maritime polar climate combines both cold and humid conditions

D. A warm and humid region has high rainfall and humidity, as such the maritime climate which are humid and the tropical climate, which are warm, combine to give a warm and humid climate

E. The continental tropical climate can be described as warm and dry, compared to the continental water bodies, due to the location being distant from and therefore, the absence of high moisture containing wind that comes from the oceans.

7 0
2 years ago
Read 2 more answers
Which statement is true about compounds? They do not form living things. They do not form nonliving things. They are formed when
oksano4ka [1.4K]

Answer:

The true statement is:

They are formed when atoms of different elements combine.

Explanation:

Compounds are formed when atoms of different elements combine.

Atoms of different elements combine with each other to attain stable electronic configuration.

The atoms can combine with each other in two different ways:

1) By sharing the electrons

2) By exchanging electrons

When they share electrons with each other, they form a covalent bond.

When they exchange electrons, they form an ionic bond.

3 0
3 years ago
What is the volume of 15.2 grams of SO2 at STP?
kiruha [24]

5.512 litres is the volume of  15.2 grams of sulphur dioxide gas at STP.

Explanation:

Data given:

mass of sulphur dioxide = 15.2 grams

conditions is at STP whech means volume = 22.4 litres

atomic mass of sulphur dioxide = 64.06 grams/mole

Number of moles is calculated as:

number of moles = \frac{mas}{atomic mass of 1 mole}

Putting the values in the equation:

number of moles = \frac{15.2}{64.06}

                              = 0.23 moles

Assuming that sulphur dioxide behaves as an ideal gas, we can calculate the volume as:

When 1 mole of sulphur dioxide occupies 22.4 litres at STP

Then 0.23 moles of sulphur dioxide occupies 22.4 x 0.23

= 5.152 litres is the volume.

5 0
3 years ago
Draw the structural formula for a hydrogen molecule (H2) and an oxygen molecule (O2). Remember that each line represents an elec
Travka [436]
See the attached photo

5 0
3 years ago
Read 2 more answers
Phthalates used as plasticizers in rubber and plastic products are believed to act as hormone mimics in humans. The value of ΔHc
jeka94

Answer:

T_f = 25.05°C

Explanation:

Given:

the value of ΔHcomb (heat of combustion) for dimethylphthalate (C10H10O4) is = 4685 kJ/mol.

mass = 0.905g of dimethylphthalate

molar mass = 194.18g dimethylphthalate

number of moles of dimethylphthalate = ???

T_i = 21.5°C

C_{calorimeter} = 6.15 kJ/°C

T_f = ???

since we have our molar mass and mass of dimethylphthalate ;we can determine the number of moles as;

0.905g of dimethylphthalate ×  \frac{1 mole (dimethylphthalate)}{194.184g(dimethylphthalate)}

number of moles of dimethylphthalate = 0.000466 moles

Heat released = moles of dimethylphthalate × heat of combustion

=  0.000466 moles × 4685 kJ

= 21.84 kJ

∴ Heat absorbed by the calorimeter =  C_{calorimeter} (T_f-T_i} )

21.84 kJ =6.15 kJ/°C * (T_f-21,5^0C)

21.84 KJ = (6.15 kJ/^0C * T_f) - (6.15 kJ/^0C*21.5^0C)

21.84 KJ = (6.15 kJ/^0C * T_f) - 132.225 kJ

21.84 KJ + 132.225 kJ = (6.15 kJ/^0C * T_f)

154.065 kJ = (6.15 kJ/^0C * T_f)

T_f = \frac{154.065kJ}{6.15kJ/^0C}

T_f =25.05°C

4 0
4 years ago
Other questions:
  • PLEASE HELP!
    14·1 answer
  • How much 0.02 m kmno4 solution should be needed if the solutions tested have a composition of 3% h2o2 by mass?
    9·1 answer
  • How do I do this whole problem?
    13·1 answer
  • 7.55 grams of P4 and 7.55 grams of O2 react according to the following reaction:
    15·1 answer
  • Name the types of waves that make up the electromagnetic spectrum from longest wavelength to shortest wavelength.
    12·1 answer
  • In an atom of barium, how many electrons have: <br> ℓ = 0<br><br> mℓ = 1
    12·1 answer
  • L
    10·1 answer
  • 8. What is the mass of 4.50 x 1022 Cu atoms?​
    5·1 answer
  • PERIODIC TABLE TEST WILL GIVE BRAINLIEST!
    13·2 answers
  • How many joules of heat are needed to change 50.0 grams of ice at -15.0 °C to steam at 120.0 °C?
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!