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3 years ago

In which of the following will the density increase?

1 answer:

4 0

Over here a lead weight moved from sea level to the top of a mountain high and a sample of chlorine gas compression the density increases for the substances.

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BLACKSHARK

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The equilibrium constant Kp for the reaction (CH3),CCI (g) = (CH3),C=CH, (g) + HCl (g) is 3.45 at 500. K. (5.00 x 10K) Calculate

Karolina [17]

Answer: The value of $K_p$ for the reaction is 6.32 and concentrations of $(CH_3)_2C=CH,HCl\text{ and }(CH_3)_3CCl$ is 0.094 M, 0.094 M and 0.106 M respectively.

Explanation:

Relation of $K_p$ with $K_c$ is given by the formula:

$K_p=K_c(RT)^{\Delta ng}$

where,

$K_p$ = equilibrium constant in terms of partial pressure = 3.45

$K_c$ = equilibrium constant in terms of concentration = ?

R = Gas constant = $0.0821\text{ L atm }mol^{-1}K^{-1}$

T = temperature = 500 K

$\Delta n_g$ = change in number of moles of gas particles = $n_{products}-n_{reactants}=2-1=1$

Putting values in above equation, we get:

$3.45=K_c\times (0.0821\times 500)^{1}\\\\K_c=\frac{3.45}{0.0821\times 500}=0.084$

The equation used to calculate concentration of a solution is:

$\text{Molarity}=\frac{\text{Moles}}{\text{Volume (in L)}}$

Initial moles of $(CH_3)_3CCl(g)$ = 1.00 mol

Volume of the flask = 5.00 L

So, $\text{Concentration of }(CH_3)_3CCl=\frac{1.00mol}{5.00L}=0.2M$

For the given chemical reaction:

$(CH_3)_3CCl(g)\rightarrow (CH_3)_2C=CH(g)+HCl(g)$

Initial: 0.2 - -

At Eqllm: 0.2 - x x x

The expression of $K_c$ for above reaction follows:

$K_c=\frac{[(CH_3)_2C=CH]\times [HCl]}{[(CH_3)_3CCl]}$

Putting values in above equation, we get:

$0.084=\frac{x\times x}{0.2-x}\\\\x^2+0.084x-0.0168=0\\\\x=0.094,-0.178$

Negative value of 'x' is neglected because initial concentration cannot be more than the given concentration

Calculating the concentration of reactants and products:

$[(CH_3)_2C=CH]=x=0.094M$

$[HCl]=x=0.094M$

$[(CH_3)_3CCl]=(0.2-x)=(0.2-0.094)=0.106M$

Hence, the value of $K_p$ for the reaction is 6.32 and concentrations of $(CH_3)_2C=CH,HCl\text{ and }(CH_3)_3CCl$ is 0.094 M, 0.094 M and 0.106 M respectively.

8 0

3 years ago

Atoms and the chemical bonds that connect them cannot be observed with your eyes, so it is necessary to use a

Lera25 [3.4K]

Answer: d. both (b) and (c)

Explanation:

Atoms are too small to be seen on microscopes, so we model them based on theories.

3 0

2 years ago

Read 2 more answers

elements on the right side of the periodic table differ from the elements on the left side in that elements on the right side

yarga [219]

Element on the right side of the periodic table differ from the elements on the left side in that elements on the right side are non metallic and tends to be gases at room temperature.

Explanation

In the periodic table there element in the right side , left side and those which are in between.

Example of element in the right side is fluorine chlorine, neon, Argon among others.

This element have higher effective nuclear charges and stabilize electrons more effectively.
there electrostatic intermolecular forces are generally weak therefore they exist in liquid or gaseous state.

7 0

3 years ago

Why is the chemical formula for sodium chloride NaCl, and not NaCI6 or Na6CI

Assoli18 [71]

Answer: NaCl

Explanation:

Here You Go :)

8 0

2 years ago

How many moles of MgS2O3 are in 173 g of the compound?

liq [111]

There are 1.27 moles in the compound.

4 0

3 years ago