1 mole ----------- 22.4 L ( at STP )
3.5 mols --------- ?
V = 3.5 x 22.4 / 1
V = 78.4 L
hope this helps!
Answer:
The electronic configuration that are incorrectly written is 1s²2s³2p⁶, 4s²3d¹⁰4p⁷, 3s¹ and 2s²2p⁴.
Explanation:
The electronic configuration of the elements corresponds to how all the electrons of an element are arranged in energy levels and sub-levels.
There are 7 energy levels —from 1 to 7— whose sublevels are described as s, p, d and f.
All electronic configurations begin with the term "1s" —corresponding to the sublevel s of level 1— so 4s²3d¹⁰4p⁷, 3s¹ and 2s²2p⁴ are incorrectly written. In addition, 4s²3d¹⁰4p⁷ is written incorrectly because is impossible to jump from the sublevel "s" to the sublevel "d" —which is found from level 3 and up— without passing through the sublevel "p".
In the case of 1s²2s³2p⁶, the wrong thing is that the sublevel "s" can only hold two electrons, not three.
The other options are correctly written.
Answer:
<span>Formula New Combination Predicted Formula
</span>
NaCl potassium + chlorine KCl
AlCl₃ aluminum + fluorine AlF₃
CO₂ tin + oxygen SnO₂
MgCl₂ calcium + bromine CaBr₂
HCl cesium + iodine CsI
<span>
CCl₄ silicon + bromine SiBr₄</span>
Explanation:
1) The question is incomplete. The first part is missing.
This is the first part of the question.
<span>Applying
the principle that the elements of a particular column in the Periodic
Table share the same chemical properties, complete the following chart.
The first one has been done for you.
</span>
2) This is the given chart:
<span>Formula New Combination Predicted Formula
</span>
Cu₂O silver + oxygen Ag₂O ← this is the example.
NaCl potassium + chlorine
<span>
AlCl₃ aluminum + fluorine </span>
CO₂ tin + oxygen
<span>
MgCl₂ calcium + bromine </span>
<span>
HCl cesium + iodine </span>
<span>
CCl₄ silicon + bromine
</span>
3) This is how you find the new formula to complete the chart.
i) NaCl potassium + chlorine
Since potassium is in the same group of sodium, you predict that in the new formula Na is replaced by K giving KCl.
ii) AlCl₃ aluminum + fluorine
Since fluorine is in the same group that Al, then you predict that in the new formula Cl is replaced by F leading to AlF₃
iii) CO₂ tin + oxygen
Since tin is in the same group that C, you predict that in the new formula C is replaced by Sn leading to SnO₂
iv) MgCl₂ calcium + bromine
Since calcium is in the same group that Mg, and bromine is in the same group that Cl, you predict thea in the new formula calcium replaces Mg and bromine replaces Cl, leading to CaBr₂
v) HCl cesium + iodine
Since H is in the same column that cesium and Cl is in the same colum that iodine, you predict that in the new formula Cs replaces H and I replaces Cl leading to: CsI
<span>
vi) CCl₄ silicon + bromine
</span>
Since silicon is in the same column that C and bromine is in the same column that Cl, you predict that in the new formula Si replaces C and Br replaces Cl, leading to SiBr₄
Answer:
THE EMPIRICAL FORMULA OF THE SUBSTANCE IS C2H5NO
Explanation:
The steps involved in calculating the empirical formula of this substance in shown in the table below:
Element Carbon Hydrogen Nitrogen Oxygen
1. % Composition 40.66 8.53 23.72 27.09
2. Mole ratio =
%mass/ atomic mass 40.66/12 8.53/1 23.72/14 27.09/16
= 3.3883 8.53 1,6943 1.6931
3. Divide by smallest
value (0.6931) 3.3883/1.6931 8.53/1.6931 1.6943/1.6931 1.6931/1.6931
= 2.001 5.038 1.0007 1
4. Whole number ratio 2 5 1 1
The empirical formula = C2H5NO
That is a steep slope for sure, no doubt about it. Hope this helps!
