Answer:
306.6g/mol
Explanation:
To calculate molecular weight you need to know how many grams ou have in a determined amount of moles of substance. As you have the mass of the sample (1.42g), you need to find how many moles are, as follows:
The reaction of the acid HX with the base YOH is:
HX + YOH → H₂O + YX
<em>1 mole of acid reacts per mole of base.</em>
<em />
In a titration, the solution turned pink when moles base = moles acid.
Moles of base that the student added (Using the volume and molarity of the solution) are:
32.48mL = 0.03248L ₓ (0.1426 moles base / L) = 0.004632 moles of base
As the titration is in equivalence point, there are 0.004632 moles of the acid
Molecular weight (Ratio between grams of sample and its moles) is:
1.42g / 0.004632 moles =
<h3>306.6g/mol</h3>
F. None of the above [Cl^(-) is oxidized]
<em>No Cl atoms are available</em> to be oxidized, only Cl^(-)ions
2Cl^(-) → Cl_2 + 2e^(-)
The substance that <em>loses electrons</em> is oxidized.
Remember <em>OIL</em> RIG (<em>O</em>xidation<em> I</em>s <em>L</em>oss of electrons) and
<em>LEO</em> the lion says GER (<em>L</em>oss of Electrons is <em>O</em>xidation).
The two chemical formulas which will correctly complete the table for lithium fluoride are: A. HF, LiOH.
<h3>What is a chemical reaction?</h3>
A chemical reaction can be defined as a chemical process that involves the continuous transformation (rearrangement) of the ionic, atomic or molecular structure of a chemical element by breaking down and forming chemical bonds, in order to produce a new chemical compound while new bonds are formed.
This ultimately implies that, chemical bonds between atoms of a chemical element are broken and then new bonds are formed in all chemical reactions.
<h3>What is a neutralization reaction?</h3>
A neutralization reaction can be defined as a type of chemical reaction between an acid and a base, which typically leads to the formation of an ionic compound (salt) and water as end products as shown below:
LiOH(aq) + HF(aq) → LiF(s) + H₂O(l)
In this context, we can infer and logically deduce that the two chemical formulas which will correctly complete the table for lithium fluoride are HF and LiOH.
Read more on neutralization reaction here: brainly.com/question/27745033
#SPJ1
The present work addresses the performance of polycaprolactone (PCL) coating on fluoride treated (MgF2) biodegradable ZK60 magnesium alloy (Mg) for biomedical application. MgF2 conversion layer was first produced by immersing Mg alloy substrate in hydrofluoric acid solution. The outer PCL coating was then prepared using dip coating technique. Morphology, elements profile, phase structure, roughness, mechanical properties, invitro corrosion, and biocompatibility of duplex MgF2/PCL coating were then characterized and compared to those of fluoride coated and uncoated Mg samples. The invivo degradation behavior and biocompatibility of duplex MgF2/PCL coating with respect to ZK60 Mg alloy were also studied using rabbit model for 2 weeks. SEM and TEM analysis showed that the duplex coating was uniform and comprised of porous PCL film (~3.3 μm) as upper layer with compact MgF2 (~2.2 μm) as inner layer. No significant change in microhardness was found on duplex coating compared with uncoated ZK60 Mg alloy. The duplex coating showed improved invitro corrosion resistance than single layered MgF2 or uncoated alloy samples. The duplex coating also resulted in better cell viability, cell adhesion, and cell proliferation compared to fluoride coated or uncoated alloy. Preliminary invivo studies indicated that duplex MgF2/PCL coating reduced the degradation rate of ZK60 Mg alloy and exhibited good biocompatibility. These results suggested that duplex MgF2/PCL coating on magnesium alloy might have great potential for orthopedic applications.
