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svetlana [45]
2 years ago
8

The density (mass/volume) of aluminum is 2.70 times. 103 kilograms per cubic meter (kg/m3). what is the mass of an aluminum cyli

nder that has a volume of 1.50 m3? 5.56 times. 10–4 kg 1.50 times. 10–3 kg 1.80 times. 103 kg 4.05 times. 103 kg
Chemistry
1 answer:
wariber [46]2 years ago
7 0

Mass of aluminum = (1.50 m^3)( 2.70 x 10^3 kg/m^3) = 4050 kg 

The intention of density is the assembly per volume of the substance. This is an intrinsic property consequently the size (or any external feature) does not change this effects.

<h3>What is Aluminum?</h3>
  • Aluminum is a silvery-white metal, the 13 elements in the regular table. One surprising fact regarding aluminum is that it's the most widespread metal on Earth, making up more than 8% of the Earth's core mass. It's also the third most standard chemical essence on our planet after oxygen and silicon.
  • The formed aluminum is in everyday use in mining, manufacturing, and trade in the United States; the formed aluminum is used with reasonable uniformity in Great Britain and typically by chemists in the United States.
  • Aluminum (Al), also spelled aluminum, chemical component, a weightless silvery-white metal of main Group 13 (IIIa, or boron group) of the periodic table. Aluminum is the most plentiful metallic component in Earth's crust and the numerous widely used nonferrous metal.

To learn motrev about  Aluminum, refer to:

brainly.com/question/246454

#SPJ4

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How many milliliters of a 0.211 M HI solution are needed to reduce 24.0 mL of a 0.354 M KMnO4 solution according to the followin
Novay_Z [31]

Answer:

The answer to your question is 242 ml

Explanation:

Data

HI 0.211 M   Volume = x

KMnO₄ 0.354 M   Volume = 24 ml

Balanced Chemical reaction

     12HI + 2KMnO₄ + 2H₂SO₄ → 6I₂ + Mn₂SO₄ + K₂SO₄ + 8H₂O

Process

1.- Calculate the moles of KMnO₄  0.354 M in 24 ml

Molarity = moles / volume (L)

moles = Molarity x volume (L)

moles = 0.354 x 0.024

moles = 0.0085

2.- From the balanced chemical reaction we know that HI and KMnO₄ react in the proportion 12 to 2. Then,

              12 moles of HI --------------- 2 moles of KMnO₄

                x                     --------------- 0.0085 moles of KMnO₄

             x = (0.0085 x 12)/2

             x = 0.051 moles of HI

3.- Calculate the milliliters of HI 0.211 M

Molarity = moles/volume

Volume = moles/molarity

Volume = 0.051/0.211

Volume = 0.242 L or Volume = 242 ml

8 0
4 years ago
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'cause it has 5 electrons in it's outer shell & every atom needs 8 electrons. So, it requires 3 more!

Hope this helps!
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