2 years ago

Expand and simplify (x + 5)(x - 2)

Mathematics

2 answers:

drek231 [11]2 years ago

6 0

The answer will be x ^ 2 + 3x - 10.

ziro4ka [17]2 years ago

5 0

Answer: *x squred +3x-10*

Step-by-step explanation:

(x+5)(x-2)

x squred-2x+5x-10

x squred +3x-10

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Find the modulus of the complex number 6-2i

Papessa [141]

Answer:

The modulus of the complex number 6-2i is:

$|z|\:=2\sqrt{10}$

Step-by-step explanation:

Given the number

$6-2i$

We know that

$z = x + iy$

where x and y are real and $\sqrt{-1}=i$

The modulus or absolute value of z is:

$|z|\:=\sqrt{x^2+y^2}$

Therefore, the modulus of $6-2i$ will be:

$z=6-2i$

$z=6+(-2)i$

$|z|\:=\sqrt{x^2+y^2}$

$|z|\:=\sqrt{6^2+\left(-2\right)^2}$

$=\sqrt{6^2+2^2}$

$=\sqrt{36+4}$

$=\sqrt{40}$

$=\sqrt{2^2}\sqrt{2\cdot \:5}$

$=2\sqrt{2\cdot \:5}$

$=2\sqrt{10}$

Therefore, the modulus of the complex number 6-2i is:

$|z|\:=2\sqrt{10}$

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Nutka1998 [239]

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Step-by-step explanation:

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