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iris [78.8K]
2 years ago
8

A 25-foot magazine rack begins 20 feet south of the checkout desk and continues south. What are the coordinates of the beginning

and end of the magazine rack? Explain or show how you got your answer.
Mathematics
2 answers:
Serggg [28]2 years ago
7 0
I need a image to help you
sineoko [7]2 years ago
6 0
Is there a image? Please put one of so
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. Kite QRST has a short diagonal of QS and a long diagonal of RT. The diagonals intersect at point P. Side QR = 17m, diagonal QS
trapecia [35]

Answer:

495 meter²

Step-by-step explanation:

In the given kite QRST,

PQ = PS = 15 meter

QR = 17 meter

We have to find the area of the kite.

Since kite is in the form of a rhombus.

and rhombus is = \frac{1}{2}  (Diagonal QS) × (Diagonal RT)

In Δ QRP,

17² = 15² + RP²

\sqrt{17^{2}-15^{2}} = RP

RP=\sqrt{289-225}

= √64 = 8 meters.

So RT = RP + PT = 8 + 25 = 33 meter.

Now area of kite = \frac{1}{2} (30) (33) = 495 meter²

6 0
3 years ago
How many ways to use when finding the quadratic equations​
vekshin1

Answer:

three

Step-by-step explanation:

1) solving for roots

2) Quadratic formula

3) By completing square

6 0
3 years ago
Can you subtract closed polynomials
netineya [11]

Answer:

Polynomials are closed under addition. When subtracting polynomials, the variables and their exponents do not change. Only their coefficients will possibly change. This guarantees that the difference has variables and exponents which are already classified as belonging to polynomials.

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Solve the proportion: 20/16 = x/80 question 19 options: 6.25 1600 100 160
Aloiza [94]
\dfrac{20}{16}=\dfrac{20:4}{16:4}=\dfrac{5}{4}\\\\\dfrac{5}{4}=\dfrac{x}{80}\ \ \ \ |cross\ multiply\\\\4x=5\cdot80\\\\4x=400\ \  \ \ |divide\ both\ sides\ by\ 4\\\\\boxed{x=100}
8 0
3 years ago
Help me ASAP please.
Leni [432]

Answer:

Step-by-step explanation:

The vertex will occur when t=-b/(2a) for the quadratic ax^2+bx+c

In this case

t=-200/(2(-16))

t=-200/-32

t=6.25

g(6.25)=-16(6.25^2)+200(6.25)

g(6.25)=625ft

So the maximum height of the rocket is 625 feet and it reaches this height at 6.25 seconds.

4 0
3 years ago
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