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Irina-Kira [14]
3 years ago
8

Find the diagonal of the rectangular prism.

Mathematics
1 answer:
KiRa [710]3 years ago
3 0

Answer:

First diagonal: 7.874

Second diagonal: 8.3666

Step-by-step explanation:

We use the Pythagorean Theorem to find these.

First diagonal = 5²+6²=c²

25+36=c²

61=c²

√61=c

c=7.874

Then we use that to find the second diagonal.

7.874²+3²=c²

61+9=c²

70=c²

√70=c

c=8.3666

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Answer:6.437376 Kilometers per Hour

Step-by-step explanation:

6 0
3 years ago
14x+2y=-10<br> solve equations for y
Ne4ueva [31]

Answer:

y = -7x - 5

Step-by-step explanation:

14x + 2y = -10

2y = -14x - 10

2y/2 = -14x/2 - 10/2

y = -7x - 5

Hope this helps -w-

3 0
3 years ago
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M+4+2-7m+6 I need to find how many’s terms are in it and what are the terms
madreJ [45]

Answer:

5 terms:  m, 4, 2, -7m, 6 are the terms in question.

Step-by-step explanation:

Note that terms here are separated from one another by either + or - signs.

m + 4 consists of two terms, since m and 4 are separated by the + operator.

2 - 7m are separated by the - operator, and so there are two terms here.

Completing the counting procedure, we get:

m (first term) + 4 (second term) + 2 (third term -7m (fourth term) + 6 (fifth term).

So, if we do NOT combine like terms, we have five (5) terms altogether.

If we DO combine like terms, we end up with two (2) terms:

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3 years ago
All zeros of polynomial function 3x^4 +14x^2 -5
Marizza181 [45]

Answer:

Correct answer:  x₁ = 1 / √3 = √3 / 3  or  x₂ = - 1 / √3 = - √3 / 3

Step-by-step explanation:

Given:

3 x⁴ + 14 x² - 5 = 0   biquadratic equation

this equation is solved by a shift  x² = t and get:

3 t² + 14 t - 5 = 0

t₁₂ = (-14 ± √14² - 4 · 3 · 5) / 2 · 3 = (-14 ± √196 + 60) / 6

t₁₂ = (-14 ± √256) / 6 = (-14 ± 16) / 6

t₁ = -5   or  t₂ = 1 / 3

the solution t₁ = -5 is not accepted because it cannot be x² = -5

we accepted  t₂ = 1 / 3

x² =  1 / 3  ⇒  

x₁ = 1 / √3 = √3 / 3  or  x₂ = - 1 / √3 = - √3 / 3

God is with you!!!

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3 years ago
The length of a photograph is 4 in. greater than its width. The area of the photograph is
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208.........not sure but this can be the ans

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