Arcsin x + arcsin 2x = π/3
arcsin 2x = π/3 - arcsin x
sin[arcsin 2x] = sin[π/3 - arcsin x] (remember the left side is like sin(a-b)
2x = sinπ/3 cos(arcsin x)-cosπ/3 sin(arc sinx)
2x = √3/2 . cos(arcsin x) - (1/2)x)
but cos(arcsin x) = √(1-x²)===>2x = √3/2 .√(1-x²) - (1/2)x)
Reduce to same denominator:
(4x) = √3 .√(1-x²) - (x)===>5x = √3 .√(1-x²)
Square both sides==> 25x²=3(1-x²)
28 x² = 3 & x² = 3/28 & x =√(3/28)
Answer:
area of the merry go round =πr²
=22/7×3²
=28.28
answer is option D
Answer:
Well it definitely can't be a function
Step-by-step explanation:
To find out if a graph is a function, you can use the vertical line test. The vertical line test is when you draw a line down the center and if it hits one point, it's a function. But, when it hits more than one point, it's not. In this case, a line would hit more than one point; meaning that they are not functions.
Answer: x = 
Step-by-step explanation: Multiply -36 and 163/9 to get -652. Add 652 to both sides then add 130 and 652 to get 782. Divide both sides by -12 then reduce the fraction 782/-12 to lowest terms by extracting and canceling out 2. The system is now solved.
