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3 years ago

(08.02

Chemistry

1 answer:

bogdanovich [222]3 years ago

7 0

Answer:

b. The molarity of the solution increases

Explanation:

The correct answer is option b, that is the molarity of the solution increases.

Because the molarity is the concentration of the solution and it is explained as the amount of solute in amount of solution.

Solution: is the solute dissolved in solvent.

So if we increases the amount of solute in solvent the concentration in terms of molarity of solution increases and if we increase amount of solvent or water then the concentration or molarity increases.

Suppose we have form a sugar solution of 1 L by adding 4 mole of sugar then what happen

Use the Molarity formula

Molarity = no. of moles / 1 L of solution

put values in the formula

Molarity = 4/ 1 L of solution = 4 M

So the molarity of solution is 4 now if we add 2 mole more sugar to the same amount of sugar and amount of solution remain the same

now the no. of moles of sugar = 6 mole

So,

Use the Molarity formula

Molarity = no. of moles / 1 L of solution

put values in the formula

Molarity = 6 mol / 1 L of solution = 6 M

So the correct option is b.

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4. What are the products (things made) of cellular respiration?

Vlad [161]

Answer:

Explanation:

Cellular respiration converts oxygen and glucose into water and carbon dioxide. Water and carbon dioxide are by- products and ATP is energy that is transformed from the process.

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3 years ago

If 33.6 grams of KCl are dissolved in 192 grams of water, what is the concentration of the solution in percent by mass?21.2% KCl

Lelu [443]

The answer here would be 14.9 %KCl and here is how I can explain why:
33.5g / 225.6g x 100% = 14.9%
<span>you are looking for % of KCl in the solution, you have to add the mass of the KCl and water to get the total mass of the solution
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4 years ago

7th grade science , please don’t get the answer from the internet :(

Liula [17]

Answer:

See the answer below

Explanation:

1. Organisms produce energy for cells by chemically breaking down and unlocking the energy locked-up within food materials in a process known as cellular respiration. The unlocked energy is then utilized for the cell's metabolic activities.

2. Cellular respiration can be aerobic or anaerobic.

Aerobic respiration involves the breakdown of carbohydrates in the presence of oxygen to yield energy in the form of ATP while carbon dioxide and water are produced as by-products.

$C_6H_1_2O_6 + 6O_2 --> 6CO_2 + 6H_2O + ATP$

Anaerobic respiration involves the breakdown of carbohydrates in the absence of oxygen to produce ATP and lactic acid as a by-product. The lactic acid is later oxidized to carbon dioxide and water to prevent it from building up.

$C_6H_1_2O_6 -> 2C_3H_6O_3 + ATP$

3. Photosynthesis and cellular respiration are both considered metabolic processes that take place in living organisms. However, photosynthesis is peculiar only to green plants and some algae while respiration is common to all living organisms. While photosynthesis is anabolic, that is, it involves the building up of materials; respiration is said to be catabolic because it involves the breaking down of materials.

During photosynthesis, inorganic products are utilized to produce carbohydrates for plants with oxygen gas released as a by-product according to the following equation:

$6CO_2 + 6H_2O --> C_6H_1_2O_6 + 6O_2$

During respiration, the food taken by living organisms is broken down to unlock the energy in it for metabolic activities according to the following equation:

$C_6H_1_2O_6 + 6O_2 --> 6CO_2 + 6H_2O + ATP$

7 0

3 years ago

A box has dimensions 0.2 mx 0.4 m x 0.6 m. What is the

AnnyKZ [126]

Answer:

$V=0.048m^3$

Explanation:

Hello,

In this case, since the volume is computed by multiplying the given dimensions as follows:

$V=0.2m*0.4m*0.6m$

The result is shown in cubic meters since each meter is also added:

$V=0.048m^3$

Best regards.

5 0

3 years ago

How many grams of carbon are present in 45.0 g of CCl4?

lisabon 2012 [21]

To determine the amount of a certain element in a compound, we use the ratio of the elements from the compound. We calculate is follows:

45.0 g CCl4 ( 1 mol CCl4 / 153.82 g CCl4 ) ( 1 mol C / 1 mol CCl4 ) ( 12.01 g C / 1 mol C ) = 3.5135 g carbon present

Hope this answers the question. Have a nice day.

5 0

4 years ago