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3 years ago

(08.02

Chemistry

1 answer:

bogdanovich [222]3 years ago

7 0

Answer:

b. The molarity of the solution increases

Explanation:

The correct answer is option b, that is the molarity of the solution increases.

Because the molarity is the concentration of the solution and it is explained as the amount of solute in amount of solution.

Solution: is the solute dissolved in solvent.

So if we increases the amount of solute in solvent the concentration in terms of molarity of solution increases and if we increase amount of solvent or water then the concentration or molarity increases.

Suppose we have form a sugar solution of 1 L by adding 4 mole of sugar then what happen

Use the Molarity formula

Molarity = no. of moles / 1 L of solution

put values in the formula

Molarity = 4/ 1 L of solution = 4 M

So the molarity of solution is 4 now if we add 2 mole more sugar to the same amount of sugar and amount of solution remain the same

now the no. of moles of sugar = 6 mole

So,

Use the Molarity formula

Molarity = no. of moles / 1 L of solution

put values in the formula

Molarity = 6 mol / 1 L of solution = 6 M

So the correct option is b.

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yawa3891 [41]

Explanation:

Since HF is a weak acid, the use of an ICE table is required to find the pH. The question gives us the concentration of the HF.

HF+H2O⇌H3O++F−HF+H2O⇌H3O++F−

Initial0.3 M-0 M0 MChange- X-+ X+XEquilibrium0.3 - X-X MX M

Writing the information from the ICE Table in Equation form yields

6.6×10−4=x20.3−x6.6×10−4=x20.3−x

Manipulating the equation to get everything on one side yields

0=x2+6.6×10−4x−1.98×10−40=x2+6.6×10−4x−1.98×10−4

Now this information is plugged into the quadratic formula to give

x=−6.6×10−4±(6.6×10−4)2−4(1)(−1.98×10−4)−−−−−−−−−−−−−−−−−−−−−−−−−−−−√2x=−6.6×10−4±(6.6×10−4)2−4(1)(−1.98×10−4)2

The quadratic formula yields that x=0.013745 and x=-0.014405

However we can rule out x=-0.014405 because there cannot be negative concentrations. Therefore to get the pH we plug the concentration of H3O+ into the equation pH=-log(0.013745) and get pH=1.86

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