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1 answer:
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Answer:
Explanation:
The half-cell reduction potentials are
Ag⁺(aq) + e⁻ ⇌ Ag(s) E° = 0.7996 V
Fe²⁺(aq) + 2e⁻ ⇌ Fe(s) E° = -0.447 V
To create a spontaneous voltaic cell, we reverse the half-reaction with the more negative half-cell potential.
The anode is the electrode at which oxidation occurs.
The equation for the oxidation half-reaction is
Answer:
moles
Explanation:
The reaction equation is given as:
4NH₃ + 5O₂ → 4NO + 6H₂O
The number of moles of O₂ that completely reacted is given as 1 mole
To solve this problem, we are going to use a stoichiometric approach from the balanced reaction equation:
5 moles of O₂ will react completely to produce 4 moles of NO
1 mole of O₂ will therefore react to produce x mole of NO
5x = 4
x = moles of NO