Question

A painter needs to cover the walls of four rooms in two coats of paint. Each room measures 4ft by 8ft and the ceiling is 10 feet high in all rooms. Each gallon of paint covers 32 square feet. How many gallons of paint does he need?

Answer 1

Answer: 60 gallons

Step-by-step explanation:

Given: Dimension of room = 4ft by 8ft

The height of ceiling =10 feet

The surface area of walls in a room which painter will paint= $2h(l+b)$

$2(10)(4+8)=20(12)=240\ square feet$

Since, A painter needs to cover the walls of four rooms in two coats of paint.

Then, the total area he need to paint =$2\times4\times240=1920\ square\ feet$

If each gallon of paint covers 32 square feet.

Then, The amount of paint he needs=$\frac{1920}{32}=60\ gallons$