Answer:
i don't know
Explanation:
I'm just trying to get points
I believe the answer is C) is different lengths of time for different types of cells.
Zero of the offspring will be bb. Since each offspring receives one allele from each parent, all will receive a B from Dad and a b from Mom, making all of the offspring heterozygous (Bb) and brown-eyed.
A night person is more active and awake at night whilst a morning person is the opposite.
Answer:
C. 40
Explanation:
Pure-breeding means that the individuals are homozygous for the genes being analyzed.
From Mendel's Law of Dominance we know that the traits that appear in the F1 are the dominant ones.
I will call:
P_ = purple flowers
pp = red flowers
L_ = long pollen
ll = round pollen
Initial cross:
P Pl/Pl x pL/pL
F1 Pl/pL
<u>Test cross</u> (cross with a homozygous recessive individual):
Pl/pL x pl/pl
<u>Expected progeny:</u>
Pl/pl = Parental (purple flowers, round pollen)
pL/pl = Parental (red flowers, long pollen)
PL/pl = Recombinant (purple flowers, long pollen)
pl/pl = Recombinant (red flowers, round pollen)
20% of the offspring have purple flowers and long pollen (PL/pl).
Every time crossing over happens in the meiosis of the F1 individual, both a <em>PL</em> gamete and a <em>pl</em> gamete form. That means that 20% of the offspring will also be pl/pl, and the total proportion of the offspring that will be recombinants will be 40%.
A distance of 1 map unit corresponds to a recombinant frequency of 1%.
A recombinant frequency of 40% therefore means that 40 map units separate the glower color and pollen shape genes.
