Ask question

Ask question

All categories

Ostrovityanka [42]

2 years ago

9

An expression is shown below: f(x) = 2x2 − 3x − 5 Part A: What are the x-intercepts of the graph of f(x)? Show your work. (2 poi

nts) Part B: Is the vertex of the graph of f(x) going to be a maximum or minimum? What are the coordinates of the vertex? Justify your answers and show your work. (3 points) Part C: What are the steps you would use to graph f(x)? Justify that you can use the answers obtained in Part A and Part B to draw the graph. (5 points) (10 points)

1 answer:

skelet666 [1.2K]2 years ago

8 0

Answer:

Step-by-step explanation:

I'm going to assume you meant 2x²-3x-5

You might be interested in

Write each of these in scientific notation <br> 1) 0.00000402<br> 2) 1,900,000

Mkey [24]

Answer:

See below in bold.

Step-by-step explanation:

1. 0.00000402

= 4.02 * 10^-6 (Counting the digits after the decimal point until we get to the 4 gives us the -6).

2. 1,900,000

= 1.9 * 10^6 ( counting the number of digits after the 1 gives us 6).

3 0

3 years ago

If you save $4500 at an interest rate of 13 percent per year, how much will you have at the end of 7 years?

GenaCL600 [577]

I thinK B hope it helps

5 0

3 years ago

Solve for x and y.<br><br> 4x-3y=16<br> -2x+4y=-2<br><br> DUE 2/7/17!

Trava [24]

$\left \{ {{4x-3y=16\:(I)} \atop {-2x+4y=-2\:(II)}} \right.$

<span>Multiply the 2nd equation by (-4). This will eliminate the x's when you add the two new equations together.
</span> $\left \{ {{4x-3y=16\:\:\:\:\:\:\:\:\:\:} \atop {-2x+4y=-2\:*(-4)}} \right.$
$\left \{ {{\diagup\!\!\!\!4x-3y=16} \atop {-\diagup\!\!\!\!4x+8y=-4}} \right.$
--------------------
$5y = 12$
$\boxed{\boxed{y = \frac{12}{5}}}\end{array}}\qquad\quad\checkmark$

Let's replace the value found in the first equation:
$4x-3y=16\:(I)$
$4x-3*( \frac{12}{5}) =16$
$4x - \frac{36}{5} = 16$
least common multiple (5)
$\frac{20x}{\diagup\!\!\!\!5} - \frac{36}{\diagup\!\!\!\!5} = \frac{80}{\diagup\!\!\!\!5}$
$20x - 36 = 80$
$20x = 80 + 36$
$20x = 116$
$x = \frac{116}{20} \frac{\div4}{\div4} \to\: \boxed{\boxed{x = \frac{29}{5} }}\end{array}}\qquad\quad\checkmark$

4 0

3 years ago

After 20 minutes Juan had it completed 12 questions, which is 0.7 of his assignment. Which percent of the Simons have he not com

egoroff_w [7]

To find the incompleted portion of the test, convert the decimal to a percentage by moving the decimal two places to the right. .7 as a percentage is 70%. subtract 70% from 100%, giving you 30%. Juan has not completed 30% of his test, or 5 questions.

4 0

3 years ago

The graph of the function f(x) = ax^2 + bx + c has vertex at (0, 2) and passes through the point

Ann [662]

Answer:

Step-by-step explanation:

You need to use vertex form of a quadratic to solve this.

Consider the vertex to be $(h,k)$

Another way of representing a quadratic is in "vertex form":

$f(x) = a(x-h)^2+k$

Now all you have to do is solve for a. You know that the vertex is $(0,2)$ and you have know the point of $(1,8)$ . Now, all you have to do is plug in these values and solve for a.

$8 = a(1-0)^2+2\\8=a(1)^2+2\\8=a+2\\a=6$

Now you know the equation is $f(x) = 6(x-0)^2+2$ , but you need it in quadratic form. All you have to do is solve is distribute the 6:

$6x^2+2$

You get:

a = 6

b = 0

c = 2

Please mark this as brainliest if it satisfies your question

7 0

3 years ago