Ask question

Ask question

All categories

3 years ago

11

Object A has a negative charge. Object A is repelled by object B. Object B is repelled by object C and attracted to object D. Wh

at are the charges on objects B, C, & D?

1 answer:

Volgvan3 years ago

5 0

Answer:

B negatively charged. C negatively charged. D positively charged.

Explanation:

If A Is negative and B is repelled by it this means that B has to have the same charge as A therefore B is negatively charged.

B is repelled By C therefore meaning they both have the same charge so C has to be negatively charged.

B is attracted to D. attraction occurs between oppositely charged objects. Therefore D has to have the opposite charge of B. Since B is negative D has to be positive in order for that attraction to occur.

You might be interested in

3. A dog walks a distance of 100 ft. in 20 s of time. What is the dog's

natta225 [31]

The answer is A.
100/20=5

8 0

3 years ago

Read 2 more answers

What is terrestrial radiation?

Feliz [49]

C) Radiation that comes from Earth...... Hope it helps, Have a nice day :)

6 0

3 years ago

Read 2 more answers

Why do magnetic bodies lose their magnetic force?

stiks02 [169]

Answer:

Well a s the temperature increases, at a certain point called the Curie temperature, a magnet will lose its strength completely. So once the metal cools, its ability to attract magnets returns, though its permanent magnetism becomes weak. In general heat is the factor that has the most effect on permanent magnets.Explanation:

8 0

4 years ago

PLEASE HELP ASAP!! CORRECT ANSWER ONLY PLEASE!!

adelina 88 [10]

A line on a graph has a downward slope

8 0

3 years ago

A Carnot heat engine uses a hot reservoir consisting of a large amount of boiling water and a cold reservoir consisting of a lar

kakasveta [241]

Answer:

$W=4037.36\ J$

Explanation:

Given:

mass of ice melted, $m=3.3\times10^{-2}\ kg$

time taken by the ice to melt, $t=5\ min=300\ s$

latent heat of the ice, $L=3.34\times 10^5\ J$

Now the heat rejected by the Carnot engine:

$Q_R=m.L$

$Q_R=0.033\times 3.34\times 10^5$

$Q_R=11022\ J$

Since we have boiling water as hot reservoir so:

$T_H=373\ K$

The cold reservoir is ice, so:

$T_L=273\ K$

Now the efficiency:

$\eta=1-\frac{T_L}{T_H}$

$\eta=1-\frac{273}{373}$

$\eta=26.81\%$

Now form the law of energy conservation:

Heat supplied:

$Q_S-W=Q_R$

where:

$Q_S=$ heat supplied to the engine

$Q_S-\eta\times Q_S=Q_R$

$Q_S(1-\eta)=Q_R$

$Q_S=\frac{11022}{1-0.2681}$

$Q_S=15059.36\ J$

Now the work done:

$W=Q_S-Q_R$

$W=15059.36-11022$

$W=4037.36\ J$

8 0

3 years ago