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3 years ago

A leopard of mass 65kg climbs 7m up a tall tree. Calculate how much gravitational potential energy it gains. Assume g=10N/kg.

Physics

1 answer:

lisabon 2012 [21]3 years ago

5 0

Answer: 4550 Joules

The formula for potential energy in gravitational field is as follows:

$E_{pot} = mgh=65kg \cdot 10 \frac{N}{kg} \cdot 7m = 4550 J$

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The sun is lower in the sky during the winter than it is during the summer. (a) how does this change affect the flux of sunlight

Svetradugi [14.3K]

the correct answer is a

8 0

4 years ago

A robot arm that controls the position of a video camera in an automated surveillance system is manipulated by a servo motor tha

lesya [120]

Answer:

W = 270.9 J

Explanation:

given,

F(x) = (12.9 N/m²) x²

work = Force x displacement

dW = F .dx

the push-rod moves from x₁= 1 m to x₂ = 4 m

integrating the above

$\int dW = \int_{x_1}^{x_2}F. dx$

$W = \int_{x_1}^{x_2}F. dx$

$W = \int_{1}^{4} (12.9 x^2) dx$

$W = 12.9\times [\dfrac{x^3}{3}]_1^4 dx$

` $W = 12.9\times [\dfrac{4^3}{3}-\dfrac{1^3}{3}] dx$

W = 270.9 J

work done by the motor is W = 270.9 J

6 0

3 years ago

2 Resistors of resistance, R = (100 +- 3) Ohm, R2 = (200+-4)Ohm are connected in Parallel and Series.

Orlov [11]

According to what I've learnt, in any expression of multiplication or division, the percentage errors of each term are added up to find the equivalent percentage error. That is, if

y=ABC

y=ABCthen% error in y= % error in A + % error in B + % error in C

For the above problem, let Rs denote series combination. Then Rs=300±7 ohm.

Let Rp denote parallel combination.

∴Rp=R1R2/R1+R2 = R1R2/Rs

Ignoring errors, we get Rp=200/3 = 66.67 ohm

%error in R1=3, %error in R2=2, %error in Rs=7/3

Hence, %error in Rp=3+2+7/3=22/3

So, error in Rp will be 22/3% of 200/3, which is approximately 4.89.

Hence, I got Rp=66.67±4.89 ohm.

However, the book used the formula described and proved here and arrived at the answer Rp=66.67±1.8ohm.

8 0

3 years ago

Read 2 more answers

For a point charge, how does the potential vary with distance from the point charge, r?

mr_godi [17]

For a point charge, how does the potential vary with distance from the point charge, r?

a constant

b. r.

c. 1/r.

d. $1/r^2$ .

e. $r^2$ .

Answer:

The correct option is C

Explanation:

Generally for a point charge the electric potential is mathematically represented as

$V = \frac{k Q }{r }$

Here we can deduce that the electric potential varies inversely with the distance i.e

$V \ \alpha \ \frac{1}{r}$

3 0

3 years ago

In order to reduce the amount of energy lost due to heat flow, electricity is delivered to our homes using _____.

erica [24]

In order to reduce the amount of energy lost due to heat flow, electricity is delivered to our homes using d. low current.

Explanation:

The presence of flow of electrons is said to be electricity. The electricity flows in one direction. The electricity enables function of the electrical devices and machines.

Heat is generated when the electricity flows from one place to another. So the energy is lost in the form of heat.

So to avoid the loss of energy, the electricity is delivered to home using low current. The strength of an electric current can be measured and represented in the unit of ampere.

4 0

4 years ago

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