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aleksandr82 [10.1K]
3 years ago
10

A young lady can paddle a canoe in a lake 7.7 m/s. She paddles downstream in a river whose current is 12.4 m/s. What is the comb

ined velocity?
Physics
1 answer:
GenaCL600 [577]3 years ago
6 0

Answer:20.1m/s

Explanation:

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How do light waves differ from sound waves?
insens350 [35]

Answer:

Light waves are electromagnetic waves while sound waves are mechanical waves. :)

5 0
2 years ago
Read 2 more answers
If the charge on the negative plate of the capacitor is 121 nano-Coulomb, how many excess electrons are on that plate? Write you
Julli [10]

Answer:

n = 756.25 giga electrons

Explanation:

It is given that,

If the charge on the negative plate of the capacitor, Q=121\ nC=121\times 10^{-9}\ C

Let n is the number of excess electrons are on that plate. Using the quantization of charges, the total charge on the negative plate is given by :

Q=ne

e is the charge on electron

n=\dfrac{Q}{e}

n=\dfrac{121\times 10^{-9}}{1.6\times 10^{-19}}

n=7.5625\times 10^{11}

or

n = 756.25 giga electrons

So, there are 756.25 giga electrons are on the plate. Hence, this is the required solution.

6 0
3 years ago
Please please help me
Illusion [34]

Answer:

amitude doesnt change

Explanation:

6 0
3 years ago
What do you mean by resistance of conductor?state it’s unit.
dalvyx [7]

Answer:

its unit is Ohm

Explanation:

Resistance means material which resist the passing current  through it and the value of resistance says how much the material is resisting the current and it temperature dependent and the unit is Ohm.

7 0
3 years ago
Find the kinetic energy of an electron whose de broglie wavelength is 34.0 nm.
dezoksy [38]
The De Broglie wavelength of the electron is
\lambda=34.0 nm=34 \cdot 10^{-9} m
And we can use De Broglie's relationship to find its momentum:
p= \frac{h}{\lambda}= \frac{6.6 \cdot 10^{-34} Js}{34 \cdot 10^{-9} m}=1.94 \cdot 10^{-26} kg m/s

Given p=mv, with m being the electron mass and v its velocity, we can find the electron's velocity:
v= \frac{p}{m}= \frac{1.94 \cdot 10^{-26} kgm/s}{9.1 \cdot 10^{-31} kg}=  2.13 \cdot 10^4 m/s

This velocity is quite small compared to the speed of light, so the electron is non-relativistic and we can find its kinetic energy by using the non-relativistic formula:
K= \frac{1}{2}mv^2= \frac{1}{2}(9.1 \cdot 10^{-31} kg)(2.13 \cdot 10^4 m/s)^2=2.06 \cdot 10^{-22} J
3 0
3 years ago
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