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Mrrafil [7]
3 years ago
7

Solve for 2 unknowns : 3a+4b=9 ; 2a+2b=6

Mathematics
1 answer:
BARSIC [14]3 years ago
3 0
Let us take the second equation first
2a + 2b = 6
Dividing both sides by 2 we get
a + b = 3
a = 3 - b
Putting the value of a in the first equation we get
3a + 4b = 9
3(3 - b) + 4b = 9
9 - 3b + 4b = 9
b = 9 - 9
   = 0
Now putting the value of b in the second equation we get
a + b = 3
a + 0 = 3
a = 3
So the value of the unknown variable a is 3 and the value of the unknown variable b is 0.

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This is solved by setting up two equations and then using one to answer the other.
The first step (use what is given to set up the two separate equations)
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 We are also told that (9 more than) 9+ (4times the smaller number) 4Y is the bigger number X
Then we combine that into 9+4Y=X
so we now have two separate equations and we can use one to solve the other. Everywhere we have X in the first equation, we will fill in with the second equation
(9+4Y) +Y = 59    [then combine like terms]
9+5Y=59            [subtract 9 from both sides]
5Y=50                   [divide both sides by 5 to isolate the Y]
Y=10                      [now plug this into either equation to solve for X]
9+4(10)=X
9+40=X
<u><em>49=X and 10=Y</em></u>
4 0
3 years ago
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