All categories

3 years ago

Solve for 2 unknowns : 3a+4b=9 ; 2a+2b=6

1 answer:

3 0

Let us take the second equation first
2a + 2b = 6
Dividing both sides by 2 we get
a + b = 3
a = 3 - b
Putting the value of a in the first equation we get
3a + 4b = 9
3(3 - b) + 4b = 9
9 - 3b + 4b = 9
b = 9 - 9
= 0
Now putting the value of b in the second equation we get
a + b = 3
a + 0 = 3
a = 3
So the value of the unknown variable a is 3 and the value of the unknown variable b is 0.

You might be interested in

What is a sample space?

Arisa [49]

Be more spasific by that

8 0

3 years ago

Which of the following represents the correct expansion of (x + 2)^5?

otez555 [7]

(x + 2)^5 = (x + 2) (x + 2) (x + 2)(x + 2)(x + 2) =
(x2 + 4x + 4)(x2+4x+4)(x+2) = ( x4 + 4x3 + 4x2 + 4x3 + 16x2 + 16x + 4x2 +16x + 16)(x+2) = ( x4 + 8x3 + 24x2 + 32x + 16)(x+2) = ( x5 + 8x4 + 24x3 + 32x2 + 16x + 2x4 + 16x3 + 48x2 + 64x + 32) =
x5 + 10x4 + 40x3 + 80x2 + 80x + 32
Answer D

8 0

3 years ago

I need help on all of them pleaseeee

dmitriy555 [2]

Step-by-step explanation:

90÷0.018=5000

90÷0.18= 500

90÷1.8 = 50

90÷18 =5

90÷180 =0.5

5 0

3 years ago

Help me find the volume please

Elena L [17]

Answer:

Step-by-step explanation:

The formula of a volume of a pyramid:

$V=\dfrac{1}{3}BH$

B - area of a base

H - height

We have the square in the base with side length a = 11 in.

Area of a base:

$B=11^2=121\ in^2$

Calculate the volume:

$V=\dfrac{1}{3\!\!\!\!\diagup_1}(121)(15\!\!\!\!\!\diagup^5)=(1)(121)(5)=605\ in^3$

3 0

3 years ago

In the figure, find the perimeter of AABC.

erma4kov [3.2K]

Answer:C. 36

Step-by-step explanation: height is 12 base is 9

12^2+9^2= 144+81=225 sq rt of 225 =15

So 12+9+15=36

4 0

3 years ago