Let V, be the rate in still water and let C = rate river current
If the boat is going :
upstream, its rate is V-C and if going
downstream, its rate is V+C,
But V = 5C, then
Upstream Rate: 5C - C = 4 C
Downstream rate: 5C+C = 6C
Time = distance/Rate, (or time = distance/speed) , then:
Upstream time 12/4C and
Downstream time: 12/.6C
Upstream time +downstream time:= 2h30 ' then:
12/4C + 12/.6C = 2.5 hours
3/C + 2/C = 5/2 (2.5 h = 5/2)
Reduce to same denominator :
5C = 10 and Rate of the current = 2 mi/h
(a) 1/12
(b) 3/12=1/4
(c) 2/12 = 1/6
(d) 3/12 + 3/12 = 6/12 = 1/2
I think it’s right ???
Wheres the graph? i cant help if theres no graph, sorry
<span>(180/pi)* asin(1.22*0.0006328/D_1)= 0.385 degree</span>
