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Svetlanka [38]
3 years ago
5

Neeeeeeed help with this.

Mathematics
1 answer:
muminat3 years ago
6 0

Answer:

Step-by-step explanation:

First system

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Write the form of the partial fraction decomposition of the rational expression. Do not solve for the constants. 37 x2 − 6x
Dvinal [7]

Answer:

\dfrac{A}{x}+\dfrac{B}{x-6}

Step-by-step explanation:

Given the function \dfrac{37}{x(x-6)}, to write the form of its partial fraction on decomposition, we will separate the two functions separated by an addition sign. The numerator of each function will be constants A and b and the denominator will be the individual factors of each function at the denominator. The partial fraction of the rational function is as shown below.

= \dfrac{37}{x(x-6)}\\\\= \dfrac{A}{x}+\dfrac{B}{x-6}

<em>Since we are not to solve for the constants, hence the partial fraction is </em>\dfrac{A}{x}+\dfrac{B}{x-6}

8 0
3 years ago
If the measure of angle 2 is 92 degrees and the measure of angle 4 is (one-half x) degrees, what is the value of x?
zavuch27 [327]

Answer: x = 184°

Step-by-step explanation: As we can see in the figure below, angles 2 and 4 are <u>Vertical</u> <u>Angles</u>, i.e., they are angles opposite each other when two lines cross. Vertical angles are always congruent.

Then,

m∠2 = m∠4

92=x.(\frac{1}{2})

92=\frac{x}{2}

Value of x is

x=92(2)

x = 184

The value of x is 184°.

4 0
3 years ago
HURRY!
yuradex [85]
-3 x + 1 > y
1/2x -1 (less than or equal to) y

See photo


3 0
2 years ago
1.A house worth $250,000 has an coinsurance clause of 90 percent. The owners insure the property for $191,250. They then have a
Arisa [49]

1. Multiply the value of the house by the percent:

250,000 x 0.9 = 225,000

Divide the amount the owner insured by the clause amount:

191,250/225,000 = 0.85

Multiply that by the amount of damage:

0.85 x 80,000 = 68,000

They will receive $68,000

2. Follow the same steps as above:

180,000 x 0.75 = 135,000

101,250 / 135,000 = 0.75

0.75 x 50,000 = 37,500

They will receive $37,500

8 0
3 years ago
Read 2 more answers
The equations -6x + 3y = 6 and x² + y = 10 intersect at the
eimsori [14]

The values of the letters in coordinates (a, b) and (c,d) are;

<u><em>a = -4</em></u>

<u><em>b = -6</em></u>

<u><em>c = 2</em></u>

<u><em>d = 6</em></u>

<u><em /></u>

We are given two equations;

-6x + 3y = 6  ---(eq 1)

x² + y = 10 ---(eq 2)

  • We are told that they intersect at coordinates; (a, b) and (c, d).

Let us make y the subject in eq 2 to get;

y = 10 - x²  --(eq 3)

  • Let us put 10 - x² into eq 1 to get;

-6x + 3(10 - x²) = 6

expanding further gives;

-6x + 30 - 3x² = 6

rearranging gives;

3x² + 6x - 24 = 0

Using online quadratic equation <em>solver</em>, we have;

x = -4 and x = 2

Putting x = -4 into eq 3 gives;

y = 10 - (-4)²

y = 10 - 16

y = -6

Putting x = 2 into eq 3 gives;

y = 10 - (2)²

y = 10 - 4

y = 6

  • Thus, the coordinates are; (-4, -6) and (2, 6)

Comparing with (a, b) and (c,d), we have;

a = -4

b = -6

c = 2

d = 6

Read more at; brainly.com/question/15165519

5 0
2 years ago
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