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Aleksandr-060686 [28]
2 years ago
13

A group of students removed the plastic insulation around a wire. They wrapped the uninsulated wire around a steel rivet 50 time

s in order to make an electromagnet. They connected the wires to a battery to make a complete circuit. They tried to pick up some steel washers, but nothing happened. Below is the advice they received from other groups in the class. What advice should they take to get their electromagnet to pick something up?
a . use insulated wire
b. wrap the wire around the nail more times
c. try picking up aluminum paper clips instead of the steel washers
d. add another d-cell to the circuit
Chemistry
1 answer:
maksim [4K]2 years ago
8 0

Answer:

d. add another d-cell to the circuit

Explanation:

To make the electromagnet pick something, the student should add another d-cell to the circuit.

Simply, the electromagnet set up is generating very weak magnetic fields.

  • To produce an electromagnet, there must be an interaction between electric fields an conductor.
  • As the wire turns around in the vicinity of the electric field, it induces magnetism.
  • The number of turns of wire here is pretty considerable.
  • But the electric field is very weak.
  • Additional d-cell in the circuit will circumvent this problem
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Molarity= mol/ liters

since the molarity is given, we can assume that we have 1.0 Liters of solution

15.6 M= mol/ 1 liters---> this means that we have 15.6 moles of HNO3

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molar mass  HNO3= 1.01 + 14.0 + (3 X 16.0)= 63.01 g/mol

15.6 mol HNO3 (63.01 g/ mol)= 983 grams HNO3

now we have to determine the grams of solution using the assumption of 1 liters of solution and the density

1 liters= 1000 mL

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When 229.0 J of energy is supplied as heat to 3.00 mol of Ar(g) at constant pressure the temperature of the sample increases by
bazaltina [42]

Answer:

The molar heat capacity at constant volume is 21.62 JK⁻¹mol⁻¹

The molar heat capacity at constant pressure is 29.93 JK⁻¹mol⁻¹

Explanation:

We can calculate the molar heat capacity at constant pressure from

C_{p,m} = \frac{C_{p} }{n}

Where C_{p,m} is the molar heat capacity at constant pressure

{C_{p} } is the heat capacity at constant pressure

and n is the number of moles

Also {C_{p} } is given by

{C_{p} } = \frac{\Delta H}{\Delta T}

Hence,

C_{p,m} = \frac{C_{p} }{n} becomes

C_{p,m} = \frac{\Delta H }{n \Delta T}

From the question,

\Delta H = 229.0 J

n = 3.00 mol

\Delta T = 2.55 K

Hence,

C_{p,m} = \frac{\Delta H }{n \Delta T} becomes

C_{p,m} = \frac{229.0}{(3.00) (2.55)}

C_{p,m} = 29.93 JK⁻¹mol⁻¹

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For, the molar heat capacity at constant volume,

From the formula

C_{p,m} = C_{v,m} + R

Where C_{v,m} is the molar heat capacity at constant volume

and R is the gas constant (R = 8.314 JK⁻¹mol⁻¹)

Then,

C_{v,m} = C_{p,m}  - R

C_{v,m} = 29.93 - 8.314

C_{v,m} = 21.62 JK⁻¹mol⁻¹

This is the molar heat capacity at constant volume

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Helium and Neon are both elements, and in particular, they belong to a group of chemical elements called noble gases. Being noble gases, they are very stable and do not react easily. 

Iron fluoride is a chemical compound consisting of the metal, iron, and the nonmetal, fluorine. When a metal and a nonmetal react to form a compound, they form ionic bonds to hold together the atoms of the different elements comprising the compound.  
3 0
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