Answer: The molar solubility of in a solution that is buffered at ph 8.00 is 0.19 M
Explanation:
Solubility product is defined as the equilibrium constant in which a solid ionic compound is dissolved to produce its ions in solution. It is represented as
We are given:
Solubility product of =
The equation for the ionization of the is given as:
1 mole of gives 1 mole of and 2 moles of
Given : pH = 8.00
Thus the molar solubility of in a solution that is buffered at ph 8.00 is 0.19 M
Answer:
S*X
Explanation:
SO PAPI MAKES THE CHEMISTRY WITH MOMMA WHEN HE STICKS IT IN THE HOLES] AND HE EATS HER
Basis of the calculation: 100g
For Carbon:
Mass of carbon = (100 g)(0.80) = 80 g
Number of moles of carbon = (80 g)(1 mole / 12g) = 20/3
For Hydrogen:
Mass of hydrogen = (100 g)(0.20) = 20 g
Number of moles of hydrogen = (20 g)(1 mole / 1 g) = 20
Translating the answer to the formula of the substance,
C20/3H20
Dividing the answer,
CH3
The molar mass of the empirical formula is:
12 + 3 = 15 g/mol
Since, the molar mass given for the molecular formula is 30.069 g/mol, the molecular equation is,
C2H6
ANSWER: C2H6
Answer:
Explanation:
To find how many moles are in the sample, you first must calculate how much one mole of C2H5OH weighs.
2(mass of C) + 5(mass of H) + (mass of O) + (mass of H)
= 2(12.01) + 5(1.008) + (16.00) + (1.008) = 46.068 g/mol
So, now that we know what 1 mole weighs, we can simply divide the weight of the sample by the weight of a mole of ethanol to get our answer.
39.2 / 46.068 = approximately 0.851 mol of ethanol