-------------------------------------------------------------------------
Given Information
-------------------------------------------------------------------------
Total number of people = 165
Adult = $6
Child = $2
Total collected = $618
-------------------------------------------------------------------------
Assumptions
-------------------------------------------------------------------------
Let x be the number of adults and y be the number of children
-------------------------------------------------------------------------
Form equations
-------------------------------------------------------------------------
Total number of people
x + y = 165
Total amount collected
6x + 2y = 618
-------------------------------------------------------------------------
Ans: The two equations are x + y = 165 and 6x + 2y = 618
-------------------------------------------------------------------------
The question is not asking for it but if you need to solve the equation to find the answer to x and y
-------------------------------------------------------------------------
Present the two equations and solve for x and y
-------------------------------------------------------------------------
x + y = 165 ------------------------- (eqn 1)
6x + 2y = 618 ------------------------- (eqn 2)
(eqn 1) :
x + y = 165
x = 165 - y ------------------------- substitute into (eqn 2)
6(165 - y) + 2y = 618
990 - 6y + 2y = 618
4y = 990 - 618
4y = 372
y = 93 ------------------------- substitute into (eqn 1)
x + y = 165
x + 93 = 165
x = 165 - 93
x = 72
x = 72 and y = 93
-------------------------------------------------------------------------
Ans: 72 adults and 93 children
-------------------------------------------------------------------------
Plug in -3 in the x.
4(2)(-3)= -24.
Answer:
33
Step-by-step explanation:
90-57=?
57+?=90
57+33=90
Answer:
10. 9
In the first question we can solve using the Pythagorean theorem. It states that the hypotenuse in a right triangle or the longest side of the triangle, squared is equal to the other 2 sides, squared. Its expressed as so: C^2 = A^2 + b^2 where c is the hypotenuse and a and b are the other sides oft eh triangle.
Therefore,
15^2 = 12^2+x^2
225=144+x^2
81=x^2
x=9
__________________________________________________________
11. x=12
In this figure, there are 2 right triangles on the sides of the square. If we can find the lengths of the base of both triangles then we can find x using the Pythagorean theorem. the total base is 21 and the square is 11. 11+a+b=21. We can assume that both triangles are congruent and therefore we can solve this equation:
11+a+b=21
a+b=10
5+5=10
b=5
a=5
The bases of the two triangles are 5 and the hypotenuse is 13. Now we can solve using the Pythagorean theorem:
c^2 = a^2+b^2
13^2=5^2+x^2
169=25+x^2
144=x^2
144= 12 x 12
x=12
__________________________________________________________
12.
The diagnol of a triangle is the hypotenuse and since the length is the square root of 3, we have all the information we need.
c^2 = a^2+b^2
2^2 = (square root of 3)^2+b^2
4=3+b^2
1=b^2
b=1
Step-by-step explanation:
