Help I need this lol!!!!!

Chemistry

1 answer:

brilliants [131]3 years ago

4 0

Answer:

green

Explanation:

You might be interested in

2 Zn + O2 → 2 ZnO

meriva

Answer:

we need 6.0 moles of zinc (Zn)

Explanation:

Step 1: Data given

Number of moles ZnO produced = 6.0 moles

Step 2: The balanced equation

2 Zn + O2 → 2 ZnO

For 2 moles Zinc we need 1 mol Oxygen to produce 2 moles Zinc oxide

Step 3: Calculate moles zinc

For 2 moles Zn we need 1 mol O2 to produce 2 moles ZnO

For 6.0 moles 2nO produced, we need 6.0 moles of zinc (Zn) and 3.0 moles of O2 to react.

3 0

3 years ago

Where is the atmosephere the most dence

likoan [24]

The Earths Surface, it’s also known as the troposphere also dense* lol

8 0

3 years ago

Read 2 more answers

Label the signals due to ha, hb, and hc in the 1h nmr spectra.

trapecia [35]

Structure along with ¹H-NMR is shown below.

Signal for Hₐ;
Based on multiplicity of of the peak, a Singlet peak (the only singlet peak present in spectrum) at 2.2 ppm was assigned to Hₐ. As the methyl group in not coupling with any other proton so it gave a singlet peak.

Signal for Hb;
Based on multiplicity of of the peak, a Quartet peak (the only quartet peak present in spectrum) at 2.4 ppm was assigned to Hb. As the methylene group in coupling with methyl group having three protons so it gave a Quartet peak.

Signal for Hc;
Based on multiplicity of of the peak, a Triplet peak (the only triplet peak present in spectrum) at 1.1 ppm was assigned to Hc. As the methyle group in coupling with methylene group having two protons so it gave a Triplet peak.

3 0

4 years ago

Write the net ionic equation for the reaction between hydrochloric acid and potassium cyanide. Do not include states such as (aq

zhannawk [14.2K]

Answer: $H^++CN^-\rightarrow HCN$ , product favoured

Explanation:

Complete ionic equation : In complete ionic equation, all the substance that are strong electrolyte and present in an aqueous are represented in the form of ions.

Net ionic equation : In the net ionic equations, we do not include the spectator ions in the equations.

When hydrochloric acid react with potassium cyanide, then it gives potassium chloride and hydrocyanic acid as products.

The complete ionic equation will be:

$H^++Cl^-+K^++CN^-\rightarrow K^++Cl^-+HCN$