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3 years ago

What is the crystalline arrangement of atoms shown here?

Chemistry

1 answer:

mixer [17]3 years ago

4 0

Answer: Answer:

"The arrangement of atoms or ions in a crystal " is described by the terms body-centered cubic and face-centered cubic.

Explanation:

Face centred cubic system explains the crystal structure where an atom is present at each cubic corner of the crystal and the centre of each cube face. Meaningfully, a closed packed plane where at each "face of the cube" atoms touch the alongside face diagonals.

Whereas in body centric cube system has the lattice point present at the 8 corners of cell and an additional one at the center of the cell. Thus, both explains how the atom or ions are placed or arranged in a crystal.

Explanation: Hope this helps :)

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The main difference between gases and liquids is that in gases A.the molecules are moving faster b.the forces between molecules

mestny [16]

I believe the answer would be A

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2 years ago

A 4.215 g sample of a compound containing only carbon, hydrogen, and oxygen is burned in an excess of oxygen gas, producing 9.58

Scilla [17]

Answer:

$\% O=27.6\%$

Explanation:

Hello,

In this case, for the sample of the given compound, we can compute the moles of each atom (carbon, hydrogen and oxygen) that is present in the sample as shown below:

- Moles of carbon are contained in the 9.582 grams of carbon dioxide:

$n_C=9.582gCO_2*\frac{1molCO_2}{44gCO_2}*\frac{1molC}{1molCO_2} =0.218molC$

- Moles of hydrogen are contained in the 3.922 grams of water:

$n_H=3.922gH_2O*\frac{1molH_2O}{18gH_2O} *\frac{2molH}{1molH_2O} =0.436molH$

- Mass of oxygen is computed by subtracting both the mass of carbon and hydrogen in carbon dioxide and water respectively from the initial sample:

$m_O=4.215g-0.218molC*\frac{12gC}{1molC} -0.436molH*\frac{1gH}{1molH} =1.163gO$

Finally, we compute the percent by mass of oxygen:

$\% O=\frac{1.163g}{4.215g}*100\% \\\\\% O=27.6\%$

Regards.

5 0

3 years ago

Someone pls pls pls help me with this question.

Arisa [49]

$\rm{\pink{\underline{\underline{\blue{REASON:-}}}}}$

⭐ Elements in which the last electron enters any one of the five d-oribitals of their respective penultimate shells are called as d-block elements .

⭐ But the last electron of Zn , Cd , Hg and Cn enters in the s-oribital of their respective ultimate shells rather than the d-oribitals of their respective penultimate shells . Therefore, these elements cannot be regarded as d-block elements .

☃️ But properties of these elements resemble to the d-block elements rather than s-block elements .

☃️ Therefore, to make the study of periodic classification of elements more rational, they are studied along with d-block elements .

✍️ Thus on the basis of properties all transition elements are d- block elements, but on the basis of electronic configuration all d -block elements are not transition elements .

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Stells [14]

Answer:

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Explanation:

you thought i would help you

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