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krek1111 [17]
3 years ago
9

Which of the following reactants can oxidize sodium?

Chemistry
1 answer:
larisa [96]3 years ago
8 0

Answer:

The answer is Aluminum

Hope this helps you

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If I have one mole of sulfur, how many atoms would that be?
krok68 [10]

Answer:

Atoms of sulfur = 9.60⋅g32.06⋅g⋅mol−1×6.022×1023⋅mol−1

Explanation:

because the units all cancel out, the answer is clearly a number, ≅2×1023 as required.

7 0
3 years ago
Which substance can be decomposed by chemical means
jolli1 [7]

Answer:

the answer is Compounds

Explanation:

Compounds are pure substances formed by the combination of elements; they can be decomposed by ordinary chemical means.

5 0
3 years ago
What is the function of the cell wall in a cell
nadya68 [22]

Answer:

To support and protect the cell.

Explanation:

The cell was (only found in plant cells) are there to help the plasma membrane and help the plant hold its structure. If the cell wall wasn't there the plant would just flop onto the ground!

-Good luck-

7 0
3 years ago
The heat capacity of water is 1cal degree'g1 (1 calorie per degree centigrade, per gram). You are given 1 gallon of water at 25
sdas [7]

Answer:

The heat needed to boil 1 gallon of water is 81,490.62 Joules.

Explanation:

Q=mc\Delta T

Where:

Q = heat absorbed or heat lost

c = specific heat of substance

m = Mass of the substance  

ΔT = change in temperature of the substance

We have :

Volume of water = V = 1 gal = 4546.09 mL

Density of water , d= 1 g/mL

mass of water = m = d × V = 1g/mL × 4546.09 mL =  4546.09 g

Specific heat of water = c = 1 Cal/g°C

ΔT = 100°C - 25°C = 75 °C

9 (boiling pint of water is 100°C)

Heat absorbed by the water to make it boil:

Q= 4546.09 g\times 1 Cal/g^oC\times 75^oC=340,956.75 Cal

1 calorie = 4.184 J

Q=\frac{340,956.75}{4.184} J = 81,490.62 J

The heat needed to boil 1 gallon of water is 81,490.62 Joules.

5 0
3 years ago
Calculate the adjusted retention times for both pentafluorobenzene and benzene if the elution time for unretained solute is 1.06
vovangra [49]

Answer:

Pentafluorobenzene: 11,92 min

Benzene: 12,14 min

Explanation:

<em>Retention time of pentafluorobenzene is 12,98 min and 13,20 min of benzene.</em>

The adjusted retention time is the time an analyte spends in the column not the stationary phase. As time of unretained solute is 1,06 min the adjusted retention time for an analyte is:

tr' = tr - 1,06min

For pentafluorobenzene:

tr' = 12,98min - 1,06min = <em>11,92 min</em>

For benzene:

tr' = 13,20 - 1,06min = <em>12,14 min</em>

<em></em>

I hope it helps!

3 0
3 years ago
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