Oxidation is the Loss of Electrons, and Reduction is the Gain of Electrons
(Remember oil rig - Oxidation Is Loss, Reduction Is Gain)
Since water loses an electron, it gets oxidised, and since carbon dioxide gains an electron, it gets reduced.
Since both oxidation and reduction occurs, it is called a Redox reaction
To make the conversion we must take into account the relationship between kBq and microcuries. Both are units that represent radioactivity activity. The relationship is:
1 kilobecquerel (kBq) = 0.027027027 microcurie
Therefore, 2.6kBq will be equal to:
Answer= That activity in microcuries will be 0.070 microcuries
Answer:
6.0 moles of H₂S are produced.
Explanation:
Let's consider the following balanced equation.
2 CH₄ + S₈ → 2 CS₂ + 4 H₂S
The molar ratio of S₈ to H₂S is 1 mol S₈: 4 mol H₂S. The moles of H₂S produced when 1.5 mol of S₈ react are:
1.5 mol S₈ × (4 mol H₂S/ 1 mol S₈) = 6.0 mol H₂S
6.0 moles of H₂S are produced, when 1.5 mol of S₈ react.
<u>Answer:</u> The mass of 97 % of NaOH solution required is 114.33 g
<u>Explanation:</u>
To calculate mass of a substance, we use the equation:
We are given:
Density of 10 % solution = 1.109 g/mL
Volume of 10% solution = 1 L = 1000 mL (Conversion factor: 1 L = 1000 mL)
Putting values in above equation, we get:
The mass of 10 % solution is 1109 g.
To calculate the mass of concentrated solution, we use the equation:
where,
are the concentration and mass of concentrated solution.
are the concentration and mass of diluted solution.
We are given:
Putting values in above equation, we get:
Hence, the mass of 97 % of NaOH solution required is 114.33 g