Answer:
1, 1, 2, 3
Explanation:
The numbers 1 and 8 both have 1 sig. fig.
The number 13 has 2 sig. figs.
The number 104 has 3 sig. figs.
Answer:
The first row of elements fits in period <u>6</u>, after the element <u>lanthanum (La)</u>. The second row of elements fits in period <u>7</u>, after the element <u>actinium (Ac). </u>
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Answer:
53.7 grams of HNO3 will be produced
Explanation:
Step 1: Data given
Mass of NO2 = 59.0 grams
Molar mass NO2 = 46.0 g/mol
Step 2: The balanced equation
3NO2 + H2O→ 2HNO3 + NO
Step 3: Calculate moles NO2
Moles NO2 = 59.0 grams / 46.0 g/mol
Moles NO2 = 1.28 moles
Step 4: Calculate moles HNO3
For 3 moles NO2 we need 1 mol H2O to produce 2 moles HNO3 and 1 mol NO
For 1.28 moles NO2 we'll have 2/3 * 1.28 =0.853 moles HNO3
Step 7: Calculate mass HNO3
Mass HNO3 = 0.853 moles * 63.01 g/mol
Mass HNO3 = 53.7 grams
53.7 grams of HNO3 will be produced
Explanation:
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Pb(C₂H₃O₂)₂ is lead(II) acetate
Pb(C₂H₃O₂)₂ --> Pb²⁺ + C₂H₃O₂²⁻
Lead(II) acetate ionizes in aqueous solution to form lead cation and acetate anion.
The chemical formula for the anion present in the aqueous solution of Pb(C₂H₃O₂)₂ is C₂H₃O₂²⁻
C₂H₃O₂²⁻ or CH₃COO⁻ is called the acetate ion.
Therefore, the correct answer is C₂H₃O₂²⁻