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Ainat [17]
2 years ago
15

A scooter travels 30 feet in 2 seconds at a constant speed. b. Complete the double number line to show the distance the scooter

travels after 1, 3, 4, and 5 seconds.
Mathematics
1 answer:
vovangra [49]2 years ago
8 0

Answer:

15 feets ; 45 feets ; 60 feets ; 75 feets

Step-by-step explanation:

Given that:

Moving at a constant speed ; Distance traveled in 2 seconds = 30 feets

The traveling speed = distance / time

Traveling speed = 30 feets / 2 seconds

Traveling speed = 15 ft/s

Distance traveled = traveling speed * time

Distance traveled after 1 second :

Time = 1 second

15ft/s * 1s = 15 ft

Distance traveled after 3 second :

Time = 3 second

15ft/s * 3s = 45 ft

Distance traveled after 4 second :

Time = 4 second

15ft/s * 4s = 60 ft

Distance traveled after 5 second :

Time = 5 second

15ft/s * 5s = 75 ft

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Given:

Polynomials

To find:

Monomial of 2nd degree with leading coefficient 3

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Monomial is an algebraic expression with only one term.

Option A: 3 n^{2}-1

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Option B: 3 n-n^{2}

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It is true.

Option D: 2n^3

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Therefore 3 n^{2} is a monomial of 2nd degree with a leading coefficient of 3.

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