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3 years ago

Name the following compound: HC2H3O2

Chemistry

2 answers:

just olya [345]3 years ago

3 0

Answer:

El ácido acético , denominado sistemáticamente ácido etanoico, es un compuesto orgánico líquido incoloro con la fórmula química CH3COOH (también escrito como CH3CO2H o C2H4O2

Explanation:

Cuando no se diluye, a veces se le llama ácido acético glacial . El vinagre es aproximadamente del 3 al 9% de ácido acético en volumen, lo que hace que el ácido acético sea el componente principal del vinagre, aparte del agua.

Leno4ka [110]3 years ago

3 0

Answer:

Acetic acid.

Explanation:

Rearranging the letters we get CH3COOH which is ethanoic or acetic acid.

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calculates the mass in kg of a granite parallelepiped (d = 2.75g / cm³) which has the following dimensions: 40 cm; 20cm; 9cm

Marianna [84]

Density=mass/volume so mass= volume*density
Volume=40*20*9
Mass=7200*2.75
=19800
Now turn it into kg which will be
19800\1000
=19.8

7 0

3 years ago

2. For the reaction, 2SO2(g) + O2(g) 2SO3(g), at 450.0 K the equilibrium con¬stant, Kc, has a value of 4.62. A system was charge

miv72 [106K]

Answer:

Q >> Kc

We have more products than reactans. To reach the equilibrium, the balance will shift to the left.

Explanation:

Step 1: Data given

Temperature = 450.0 K

Kc = 4.62

When Kc > Q, we have more reactants than products. To reach the equilibrium, the balance will shift to the right

When Kc < Q, we have more products than reactans. To reach the equilibrium, the balance will shift to the left.

When Kc = Q,the equiation isatequilibrium

[SO3] = 0.254 M

[O2] = 0.00855 M

[SO2] = 0.500 M

Step 2: The balanced equation

2SO2(g) + O2(g) ⇄ 2SO3(g)

Step 3: Calculate the Q

Q = [SO3]² / [O2][SO2]²

Q = 0.254²/ (0.500 * 0.00855²)

Q = 1765

Q >> Kc

We have more products than reactans. To reach the equilibrium, the balance will shift to the left.

6 0

4 years ago

Read 2 more answers

If you were to use Lewis theory to predict the formula for the compound between rubidium and fluorine, it would most likely be:

goldenfox [79]

<u>Answer:</u> The formula of the compound formed between rubidium and fluorine is RbF

<u>Explanation:</u>

Ionic bond is defined as the bond which is formed by complete transfer of electrons from one atom to another atom.

The atom which looses the electron is known as electropositive atom and the atom which gains the electron is known as electronegative atom. This bond is usually formed between a metal and a non-metal.

Rubidium is the 37th element of the periodic table having electronic configuration of $1s^22s^22p^63s^23p^64s^23d^{10}4p^65s^1$

This will loose 1 electron to form $Rb^+$ ion

Fluoride is the 9th element of the periodic table having electronic configuration of $1s^22s^22p^5$

This will gain 1 electron to form $F^-$ ion

To form $RbF$ compound, 1 rubidium ion is needed to neutralize the charge on fluoride ion

The formation of the given compounds is shown in the image below.

4 0

3 years ago

How many moles of molecular oxygen (o2) are consumed in the complete combustion of one mole of pentane (c5h12)?

Mama L [17]

C₅H₁₂ + 8O₂ = 5CO₂ + 6H₂O

5CO₂ - 10O
6H₂O - 6O
16O - 8O₂

8 moles of molecular oxygen are consumed

3 0

3 years ago

What is the total number of sp2-hybridized carbon atoms present in the fluorophore used in the experiments

Mandarinka [93]

Answer:

Explanation:

The structure of fluorophore used in the experiments has been drawn in the attachment. And from the drawing counting we can say that there are 9 sp2-hybridized carbon atoms present. Fiuorophores are a fluorescent chemical compound that can re-emit light upon light excitation. Normally used to produce absorbance and emission spectra.

3 0

4 years ago