Helppppppppppppppppppppp due in 2hrs plz wacth for more questions
1 answer:
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Answer:
It can hold up to of waste
<em></em>
Step-by-step explanation:
Given
-- Diameter
-- height
Required
Determine the amount of waste it can hold
This simply means that we calculate the volume of the cylindrical container.
And this is calculated using:
Where
and
So, we have:
<em>Hence, it can hold up to </em><em> of waste</em>
Answer:
<h3>The possibilities of length and width of the rectangle are </h3><h3>x=1, y=0.24;</h3><h3>x=0.5, y=0.48;</h3><h3>x=0.25, y=0.96;</h3><h3>x=2, y=0.12</h3>Step-by-step explanation:
Given that the area is 0.24 square meter
The area of a rectangle is given by
square units
Let x be the length and y be the width.
Since the area is 0.24 square meter, we have the equation:
, with x and y measures in meters
If we want to know some possibilities of x and y, we can assume a value for one of them, and then calculate the other one using the equation.
Now choosing some values for "x", we have:
Put x = 1
∴ y = 0.24
Now put x = 0.5 we get
∴ y = 0.48
Put x = 0.25
∴ y = 0.96
Put x = 2
∴ y = 0.12