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BabaBlast [244]
3 years ago
11

1) Convert the following:I) 65 kg into gii) 87570 seconds into houriii) 7.5 km into m​

Physics
2 answers:
DiKsa [7]3 years ago
4 0

Answer:

65000g

24.325 hrs

7500m

Natalka [10]3 years ago
3 0

Answer:

I) 65000 g   II)24.325 hours  III)7500 m

Explanation:

I) 1 kg = 1000 g

65 kg = 65 * 1000 g = 65000 g

II) 1 hour = 3600 seconds

1 second = 1/3600 hours

87570 seconds = 87570 * 1/3600 hours =24.325 hours

III) 1 km = 1000 m

7.5 km = 7.5 * 1000 m = 7500 m

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Answer:

LED bulb = 0.145 A

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CFL bulb = 0.218 A

Explanation:

Given:

Power rating of LED bulb (P₁) = 16 W

Power rating of incandescent bulb (P₂) = 100 W

Power rating of CFL bulb (P₃) = 24 W

Terminal voltage across the circuit (V) = 110 V

We know that, power is related to terminal voltage and current drawn as:

P=VI

Express this in terms of 'I'. This gives,

I=\frac{P}{V}

Now, calculate the current drawn in each bulb using their respective values.

For LED bulb, P_1=16\ W, V=110\ V

So, current drawn is given as:

I_1=\frac{16\ W}{110\ V}=0.145\ A

For incandescent bulb, P_2=100\ W, V=110\ V

So, current drawn is given as:

I_2=\frac{100\ W}{110\ V}=0.909\ A

For CFL bulb, P_3=24\ W, V=110\ V

So, current drawn is given as:

I_3=\frac{24\ W}{110\ V}=0.218\ A

Therefore, the currents drawn through LED bulb, incandescent bulb and CFL bulb are 0.145 A, 0.909 A and 0.218 A respectively.

5 0
3 years ago
What phenomena provides <br> evidence of electric fields in the atmosphere
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- A ship's total weight is equal to the weight of the water it displaces. If you want to calculate the
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Answer:

c. the volume of the part of the ship that lies below the water's surface.

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As stated in the problem, Archimedes' Principle tells us that that buoyant force on an object is equal to the weight of fluid it displaces.  The volume of water that a ship displaces is the volume it occupies below the surface.

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3 years ago
A car traveling at 30 m/s north slows to a stop in 15 seconds. What is the acceleration? PLEASE HELP
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3 years ago
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What is the energy of a mole of photons that have a wavelength of 413 nm? (h = 6.626 × 10⁻³⁴ J • s and c = 3.00 × 10⁸ m/s)
Triss [41]

Answer:

Energy of one mole of photon will be 2.89\times 10^5J    

Explanation:

We have given wavelength of photon \lambda =413nm=413\times 10^{-9}m

Velocity of light is given c=3\times 10^8m/sec

Plank's constant h=6.626\times 10^{-34}Js

Energy of the photon is given by E=\frac{hc}{\lambda }=\frac{6.626\times 10^{-34}\times 3\times 10^8}{413\times 10^{-9}}=0.048\times 10^{-17}J

We have to find the energy of one mole of photon

One mole of photon is equal to 6.023\times 10^{23}photon

So energy of one mole of photon will be equal to 6.023\times 10^{23}\times 0.048\times 10^{-17}=2.89\times 10^5J

So energy of one mole of photon will be 2.89\times 10^5J

6 0
3 years ago
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