molecular cloud <interstellar cloud <1 Msun protostar <1 Msun star <intercloud gas
Explanation:
<u>Molecular cloud-</u> They are a variety of interstellar cloud in which molecular hydrogen can sustain themselves. They have a very low temperature ranging from -440 to -370 degrees Fahrenheit or between<u> 10 to 50 Kelvin. </u>Owing to their extremely low temperature, they appear mostly dark when viewed through telescopes.
<u>Interstellar cloud-</u> They are a congregation of a large number of interstellar gases, dust and plasma in any galaxy or universe. They have varying temperature depending on their proximity to a star. E.g. Neutral hydrogen atom clouds have a temperature of around <u>just 100 Kelvin</u> while those in the near vicinity of a star have temperatures as high as 10,000 Kelvin.
<u>1 Msun star-</u> These stars have temperature anywhere between <u>5300 and 6000 Kelvin</u>. The main source of such high surface temperature is nuclear fusion process where elemental hydrogen molecules are fused to form helium molecules.
<u>1 Msun protostar-</u> protostar is rather a young star which is still in formation phase (i.e. gathering mass from the parent molecular cloud). They have temperature anywhere between <u>2000-3000</u> kelvin and are accompanied by dust usually.
<u>Intercloud gas- </u>These are the remainder gases that are spread throughout the interstellar space. This Intercloud gas is divided into warm intercloud medium and extremely hot coronal gas with temperatures comparing to Sun’s corona. Warm intercloud forms the dominant part of intercloud gas with a temperature around <u>8000 Kelvin</u>.
The northward components of the resultant displacement is 40.96 m and the westward components of the resultant displacement of the bird from its nest is 28.68 m.
<h3>
Displacement of the bird</h3>
The displacement of the bird is the change in the position of the bird.
<h3>Vertical component of the bird's displacement </h3>
Vy₁ = -25 m x sin(55)
Vy₁ = -20.48 m
Vy₂ = 75 m x sin(55)
Vy₂ = 61.44 m
Total vertical displacement = 61.44 m - 20.48 m = 40.96 m
<h3>Horizontal component of the bird's displacement </h3>
Vx₁ = -25 m x cos(55)
Vx₁ = -14.34 m
Vx₂ = 75 m x cos(55)
Vx₂ = 43.02 m
Total horizontal displacement = 43.02 m - 14.34 m = 28.68 m
Learn more about displacement here: brainly.com/question/2109763
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Answer:
No, scalar and vector quantities are two different categories of a quantity.
So vector could not be considered to be scalar too.
<em>But turning a vector to a scalar is possible</em>. Only remove the direction of movement.
Answer:
The radius is (0.04m) meters
Explanation:
F = mv^2/r
m is the mass of the helicopter = m kg
v is the speed of the helicopter = 20 m/s
F is force supplied by the jet = 10,000 N
10,000 = m×20^2/r
r = 400m/10,000 = 0.04m
The radius is (0.04m) meters
Answer:
190 000 m
Explanation:
1km = 1000m
--> 190 km = 190 x 1000 = 190 000 m