If the lightbulb A in the circuit shown in the image burned out, the path for the current to flow is disrupted because one of its terminals is connected direct to the source. So, there will be no current through the lightbulbs B, C, and D, and they will turn off. Similarly it will happen, if the lightbulb D burned out.
If the lightbulb B burned out the current will continue circulating through the lightbulbs A, C, and D, because lightbulb B is connected in parallel. Similarly it will happen, if the lightbulb C burned out.
Answer:
True! First step is to make objective observations.
Answer:
Therefore the horizontal range = 294897.96 m.
Explanation:
Range of a projectile: The range is defined as the horizontal distance from the point of projection to the point where the projectile hit the projection plane again. The S.I unit of range is Meter (m).
It can be expressed mathematically as
R = u²sin2∅/g............................. Equation 1
Where R = Horizontal range, ∅ = angle of projection, u = initial velocity, g = acceleration due to gravity.
<em>Given: u = 1700 m/s, </em>∅ = 55°,
Constant: g = 9.8 m/s²
Substituting these values into equation 1
R = (1700²sin55)/9.8
R = 2890000/9.8
R = 294897.96 m.
Therefore the horizontal range = 294897.96 m.
Answer:
(A) 0.3488 rad/sec
(B) 124.246 m
Explanation:
We have given car completes one revolution in 18 sec'
So time period T= 18 sec
Tangential speed v = 43.4 m/sec
(A) Angular velocity is given by 
(B) Tangential velocity is given v = 43.4 m /sec
We know that 
