What amount of charge passes through a 3.0 amp television in 1.3 hours?
1 answer:
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The velocity of the pitcher at the given mass is 0.1 m/s.
The given parameters:
- <em>Mass of the pitcher, m₁ = 50 kg</em>
- <em>Mass of the baseball, m₂ = 0.15 kg</em>
- <em>Velocity of the ball, u₂ = 35 m/s</em>
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Let the velocity of the pitcher = u₁
Apply the principle of conservation of linear momentum to determine the velocity of the pitcher as shown below;
m₁u₁ = m₂u₂
Thus, the velocity of the pitcher at the given mass is 0.1 m/s.
Learn more about conservation of linear momentum here: brainly.com/question/13589460
Answer:
The velocity of the other fragment immediately following the explosion is v .
Explanation:
Given :
Mass of original shell , m .
Velocity of shell , + v .
Now , the particle explodes into two half parts , i.e .
Since , no eternal force is applied in the particle .
Therefore , its momentum will be conserved .
So , Final momentum = Initial momentum
The velocity of the other fragment immediately following the explosion is v .
Answer:
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