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aalyn [17]
2 years ago
13

The tiny planet Mercury has a radius of 2400 km and a mass of 3.3 times 10^23 kg.

Physics
2 answers:
Reil [10]2 years ago
7 0

Answer:

I think that you need the gravitational acceleration of mercury

so we will use Newton's gravitational law :

gravitational acceleration = G*m/2

G is the gravitational constant = G = 6.673×10^-11 N m^2 kg^-2

after substitution : m^7x r67 / 11

6.673×10^-11 * 3.2x10^23 / (2.43x10^6)^2

using calculator : 2.00007899999

gravitational acceleration of mercury = 3.61625 m/s^2

pls give me brainliest

Explanation:

Korolek [52]2 years ago
3 0

Answer:

is7byfegl ftna%$×$<yqjdfvwcidfcbi

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The Sun is expected to undergo hydrogen fusion for a total of _____ years. a million 10 million a billion 10 billion 100 billion
Elanso [62]
The correct answer is 10 billion years. The Sun is expected to undergo hydrogen fusion for a total of 10 billion years. The Sun generates its energy by nuclear fusion of hydrogen and produces helium nucleus. It fuses 620 million metric tons every second.
3 0
3 years ago
Read 2 more answers
Merry-go-rounds are a common ride in park playgrounds. The ride is a horizontal disk that rotates about a vertical axis at their
Vera_Pavlovna [14]

Answer:

A = 2.36m/s

B = 3.71m/s²

C = 29.61m/s2

Explanation:

First, we convert the diameter of the ride from ft to m

10ft = 3m

Speed of the rider is the

v = circumference of the circle divided by time of rotation

v = [2π(D/2)]/T

v = [2π(3/2)]/4

v = 3π/4

v = 2.36m/s

Radial acceleration can also be found as a = v²/r

Where v = speed of the rider

r = radius of the ride

a = 2.36²/1.5

a = 3.71m/s²

If the time of revolution is halved, then radial acceleration is

A = 4π²R/T²

A = (4 * π² * 3)/2²

A = 118.44/4

A = 29.61m/s²

7 0
3 years ago
A 0.15 g honeybee acquires a charge of 22 pC while flying. The electric field near the surface of the earth is typically 100 N/C
Rus_ich [418]

Answer:

1.50\ *10^{-6} }

Explanation:

Given

e=100 N/C

M=0.15 g

q=\ 22\  pC\\=\ 22\ *10^{-2}

The  ratio of the electric force on the bee to the bee's weight can be determined by the following formula

\frac{fe}{M*9.81}

\frac{22*10^{-12\ *\ 100} }{0.15*\ 10^{-3} *\ 9.81}

=\ 1.50\ *10^{-6}

4 0
3 years ago
What does the magnitude of centripetal acceleration depend on ?
MariettaO [177]

Explanation:

Centripetal acceleration ac is the acceleration experienced while in uniform circular motion. It always points toward the center of rotation. It is perpendicular to the linear velocity v and has the magnitude ac=v2r;ac=rω2 a c = v 2 r ; a c = r ω 2 .

3 0
3 years ago
Describe the sun. Include its structure (layers), relative size, location, and effects of its magnetic field. Where does the sun
Salsk061 [2.6K]

Answer: Nuclear fusion.

Explanation: The sun is a medium-sized star, its radius is  695.510 km and its mass is equivalent to that obtained by bringing together about 110 planets equal to Earth (6371 km is its radius).

It has six layers: The core, the radioactive zone, the convective zone, the photosphere, the chromosphere and the corona.

Magnetic field disruptions near active regions can generate strong explosions in the sun such as sun flashes and coronal mass ejections. The degree of complexity of the sun´s magnetic field increases and decreases with the course of each sunspot cycle.  

Sir Arthur Eddington was the first to evaluate all the data and dared to conjecture that nuclear fusion, the process that creates heavy elements from the fusion of lighter ones, could be responsible for the great production of the sun´s energy; this process make the sun´s energy was taken for the earth and the planet get back to the sun recycled energy. The sun has a very large and complex magnetic field; the average magnetic field of the sun is approximately 1 Gauss, almost twice as strong as the average magnetic field of the Earth´s surface (approximately 0.5 Gauss). Because the surface of the sun is more than 12.000 times larger than the Earth, the overall influence of the sun´s magnetic field is immensely large.

6 0
3 years ago
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