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Bad White [126]
2 years ago
7

Thinking about planck's law, which star would give off the most orange light?

Physics
1 answer:
stiks02 [169]2 years ago
4 0

Thinking about Planck's law, the Red star would give off the most orange light.

According to Planck's Law, distinct atoms and molecules can emit or take in power in discrete portions simplest. The smallest amount of strength that can be emitted or absorbed inside the form of electromagnetic radiation is called quantum.

Planck's Law describes the quantity of spectral radiance at a particular wavelength radiated through a black body in equilibrium. The equation is E=hv.

The floor temperature of a celeb determines the color of mild it emits. Blue stars are warmer than yellow stars, which are hotter than red stars. The bright orange celebrity Arcturus is particularly noteworthy for its massive right motion, The color is a characteristic of their floor temperatures.

Learn more about plank's law here:-brainly.com/question/1673393

#SPJ4

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gwendolyn has a mass of 17 kg. she is riding her scooter at 1.15 m/s to the right when she runs into maya. maya has a mass of 13
kykrilka [37]
Inelastic collision happens when two objects joined and move together after the collision

7 0
3 years ago
Ignoring the electron spin what is the largest possible energy difference, if the magnetic field is 2.02 tesla?
Nonamiya [84]

Complete Question:

When specially prepared Hydrogen atoms with their electrons in the 6f state are placed into a strong uniform magnetic field, the degenerate energy levels split into several levels. This is the so called normal Zeeman effect.

Ignoring the electron spin what is the largest possible energy difference, if the magnetic field is 2.02 Tesla?

Answer:

ΔE = 1.224 * 10⁻²² J

Explanation:

In the 6f state, the orbital quantum number, L = 3

The magnetic quantum number, m_{L} = -3, -2, -1, 0, 1, 2, 3

The change in energy due to Zeeman effect is given by:

\triangle E = m_{L} \mu_{B} B

Magnetic field B = 2.02 T

Bohr magnetron, \mu_{B} = 9.274 * 10^{-24} J/T

\triangle E = 6 * 9.274 * 10^{-24} * 2.2\\

ΔE = 1.224 * 10⁻²² J

5 0
3 years ago
A 11.0 kg satellite has a circular orbit with a period of 1.80 h and a radius of 7.50 × 106 m around a planet of unknown mass. I
Anuta_ua [19.1K]

Answer:

Explanation:

Expression for times period of a satellite can be given as follows

Time period T = 1.8 x 60 x 60

= 6480

T² = \frac{4\times \pi^2\times r^3}{GM} where T is time period , r is radius of orbit , G is gravitational constant and M is mass of the satellite.

6480² = 4 x 3.14² x 7.5³ x 10¹⁸ / GM

GM = 4 x 3.14² x 7.5³ x 10¹⁸ / 6480²

= 3.96 X 10¹⁴

Expression for acceleration due to gravity

g = GM / R² where R is radius of satellite

20 = 3.96 X 10¹⁴ / R²

R² = 3.96 X 10¹⁴ / 20

= 1.98 x 10¹³ m

R= 4.45 x 10⁶ m

8 0
3 years ago
Okay! Last question was a warm-up question. And now to get your brain thinking some more, how about another one?:
den301095 [7]
The correct answer is a fishhook
5 0
3 years ago
Ms. Stafford wants to try racing with a push start. A student pushes her at 5 m/s before the rocket kicks in. The rocket still o
Gnom [1K]
The initial velocity of Ms. Stafford is v_0 = 5 m/s, while her acceleration is 
a=4 m/s^2
This is a uniform accelerated motion, so we can calculate the total distance travelled by Ms. Stafford in a time of t=7.0 s using the law of motion for a uniform accelerated motion:
S=v_0t +  \frac{1}{2} at^2 = (5 m/s)(7.0 s)+ \frac{1}{2}(2 m/s^2)(7.0 s)^2 = 84 m
8 0
3 years ago
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