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Anna007 [38]
3 years ago
10

Which of these redox reactions is spontaneous as written?

Chemistry
1 answer:
natta225 [31]3 years ago
7 0
The answer of this question is A
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Simply parmanent tissue real life application please help it's for my project ​
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The simple tissues are parenchyma, sclerenchyma and collenchyma. Chlorenchyma is a parenchyma, having chloroplast. It is a simple permanent tissue, having chloroplast.
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If you wanted to know how big a tiger is which measurements would you use?
Elan Coil [88]
I think the answer is
D. Meter Second
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3 years ago
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1.Which Statement best describes the use of a catalyst in a fuel cell?
mixer [17]

Answer: D. It Increases reaction rates.

Explanation:

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2 years ago
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In a hypothetical atom, electron N transitions between energy levels, giving off orange light in the transition. In the same ato
Zielflug [23.3K]

Answer : Electron P has greater energy difference than the Electron N.

Explanation :  

Wavelength range of violet light = 400 - 500 nm

Wavelength range of orange light = 600 - 700 nm

The Planck's equation is,

E=\frac{h\times c}{\lambda}

where,

E = energy of light

c = speed of light

\lambda = wavelength of light

According to the Planck's equation, wavelength and energy follow inverse relation. As the wavelength increases, energy decreases.

From the given spectrum, the wavelength of violet light is less. We conclude that When electron P gives violet light on transition it means that energy difference between the energy level was high.

From the given spectrum, the wavelength of orange light is more. We conclude that When electron N  gives orange light on transition it means that energy difference between the energy level was low.

So, Electron P which gives violet light on transition has greater energy difference than the Electron N.


6 0
3 years ago
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An ideal gas in a sealed container has an initial volume of 2.80 L. At constant pressure, it is cooled to 18.00 °C, where its
Aleks04 [339]

Answer:

T_1=-91.18\°C

Explanation:

Hello there!

In this case, given the T-V variation, we understand it is possible to apply the Charles' law as shown below:

\frac{T_1}{V_1}= \frac{T_2}{V_2}

Thus, since we are interested in the initial temperature, we can solve for T1, plug in the volumes and use T2 in kelvins:

T_1= \frac{T_2V_1}{V_2}\\\\T_1= \frac{(18.00+273.15)K(1.75L)}{(2.80L)}\\\\T_1=182K-273.15\\\\T_1=-91.18\°C

Best regards!

6 0
3 years ago
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