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3 years ago

Arrange the following substances in order of increasing boiling point CH3OH, CH4, CH3CH2OH, HOCH2CH2OH Multiple Choice O CH3OH

Chemistry

1 answer:

Tju [1.3M]3 years ago

8 0

Answer:

The answer is: CH₄ < CH₃OH < CH₃CH₂OH < HOCH₂CH₂OH

Explanation:

Boiling point refers to the temperature at which the pressure exerted by the surrounding on the liquid is equal to the vapor pressure of the liquid. The boiling point increases as the molar mass of the substance increases.

Since the molar mass increases in the order:

CH₄ < CH₃OH < CH₃CH₂OH < HOCH₂CH₂OH

Therefore, the order of increasing boiling point:

CH₄ < CH₃OH < CH₃CH₂OH < HOCH₂CH₂OH

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Answer:

8721.132 Kg.

Explanation:

The following data were obtained from the question:

Density (D) of silver = 10.5 g/cm³

Length (L) of silver = 0.94 m

Mass (m) of silver =.?

Next, we shall determine the volume of silver. This can be obtained as follow:

Volume = Length × Length × Length

Volume = L × L × L

Volume = L³

Length (L) of silver = 0.94 m

Volume (V) of silver =?

Volume (V) of silver = 0.94³

Volume (V) of silver = 0.830584 m³

Next, we shall convert 0.830584 m³ to cm³. This can be obtained as follow:

1 m³ = 1×10⁶ cm³

Therefore,

0.830584 m³ = 0.830584 m³ / 1 m³ × 1×10⁶ cm³

0.830584 m³ = 830584 cm³

Therefore, 0.830584 m³ is equivalent 830584 cm³.

Thus, the volume of the silver is 830584 cm³.

Next, we shall determine the mass of the silver. This can be obtained as follow:

Density (D) of silver = 10.5 g/cm³

Volume of the silver = 830584 cm³.

Mass of silver =.?

Density = mass /

10.5 = mass of silver /830584

Cross multiply

Mass of silver = 10.5 × 830584

Mass of silver = 8721132 g

Finally, we shall convert the mass of silver, 8721132 g to kilogram (kg). This can be obtained as follow:

1000 g = 1 Kg

Therefore,

8721132 g = 8721132 g / 1000 g × 1 Kg

8721132 g = 8721.132 Kg

Therefore, the mass of each cube of silver is 8721.132 Kg

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