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2 years ago

12

A bacteria culture doubles every hour. If there are 15000 bacteria now, how many bacteria were there 6 hours ago? Use an exponen

tial equation and answer to nearest bacterium

1 answer:

Kamila [148]2 years ago

7 0

23.4375 or 24.0 is the bacteria count after 6 hours.

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The beginning balance in Cash was $3,500. Additional cash of $2,000 was received. Checks were written totaling $2,500. The cash

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3500+2000 = $5500
5500-2500 = $3000 so it would be 3000

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2 years ago

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What is the product?(4x)(-3x^8)(-7^3)

kicyunya [14]

Answer:

4116x^9

Step-by-step explanation:

(4x)(-3x^8)(-7^3)

(-12x^9)(-343)

4116x^9

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3 years ago

How do I find the missing sides of this triangle by using trigonometry

Lemur [1.5K]

Step-by-step explanation:

Use SOH-CAH-TOA.

Sine = Opposite / Hypotenuse

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Tangent = Opposite / Adjacent

You're given an angle, the adjacent side to that angle, and the hypotenuse. So use cosine.

Cosine = Adjacent / Hypotenuse

cos 37° = 48 / x

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x cos 37° = 48

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x = 48 / cos 37°

If desired, use a calculator to evaluate.

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3 years ago

What is the domain of f/g, given f(x)=x+2 and g(x)=x-7?

kodGreya [7K]

Answer:

(-∞,7) U (7,∞)

Step-by-step explanation:

f(x)= x+2

g(x) = x-7

$\frac{f(x)}{g(x)} =\frac{x+2}{x-7}$

Here we have x-7 in the denominator

To find domain we set the denominator =0 and solve for x

x-7=0

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So we ignore 7 for x

Hence domain is

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2 years ago

Read 2 more answers

A certain firm has plants A, B, and C producing respectively 35%, 15%, and 50% of the total output. The probabilities of a non-d

Sliva [168]

Answer:

There is a 44.12% probability that the defective product came from C.

Step-by-step explanation:

This can be formulated as the following problem:

What is the probability of B happening, knowing that A has happened.

It can be calculated by the following formula

$P = \frac{P(B).P(A/B)}{P(A)}$

Where P(B) is the probability of B happening, P(A/B) is the probability of A happening knowing that B happened and P(A) is the probability of A happening.

-In your problem, we have:

P(A) is the probability of the customer receiving a defective product. For this probability, we have:

$P(A) = P_{1} + P_{2} + P_{3}$

In which $P_{1}$ is the probability that the defective product was chosen from plant A(we have to consider the probability of plant A being chosen). So:

$P_{1} = 0.35*0.25 = 0.0875$

$P_{2}$ is the probability that the defective product was chosen from plant B(we have to consider the probability of plant B being chosen). So:

$P_{2} = 0.15*0.05 = 0.0075$

$P_{3}$ is the probability that the defective product was chosen from plant B(we have to consider the probability of plant B being chosen). So:

$P_{3} = 0.50*0.15 = 0.075$

So

$P(A) = 0.0875 + 0.0075 + 0.075 = 0.17$

P(B) is the probability the product chosen being C, that is 50% = 0.5.

P(A/B) is the probability of the product being defective, knowing that the plant chosen was C. So P(A/B) = 0.15.

So, the probability that the defective piece came from C is:

$P = \frac{0.5*0.15}{0.17} = 0.4412$

There is a 44.12% probability that the defective product came from C.

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3 years ago