Not in my oppinion it easy for me if you need help go to JISKHA homework helper it give all answer to test some times may you please mark me as brainlyest love you guys and have a bless Day <3

Step-by-step explanation:

7 0

3 years ago

To study the output of a machine that fills boxes with cereal, a quality control engineer weighed 150 boxes of Brand X cereal. T

scoundrel [369]

Answer:

$\sigma = 0.07770$

Step-by-step explanation:

Given

The above table

Required

The standard deviation

First, calculate the class mid-point. This is the average of the class interval.

The mid-point x is:

$x_1 = \frac{1}{2}(15.3 + 15.6) =\frac{1}{2} * 30.9 = 15.45$

$x_2 = \frac{1}{2}(15.6 + 15.9) =\frac{1}{2} * 31.5 = 15.75$

$x_3 = \frac{1}{2}(15.9 + 16.2) =\frac{1}{2} * 32.1 = 16.05$

$x_4 = \frac{1}{2}(16.2 + 16.5) =\frac{1}{2} * 32.7 = 16.35$

$x_5 = \frac{1}{2}(16.5 + 16.8) =\frac{1}{2} * 33.3 = 16.65$

So, we have:

$\begin{array}{cccccc}x & {15.45} & {15.75} & {16.05} & {16.35} & {16.65} \ \\ f & {14} & {25} & {84} & {18} & {9} \ \end{array}$

Calculate mean

$\bar x = \frac{\sum fx}{\sum f}$

$\bar x = \frac{15.45 * 14 + 15.75 * 25 + 16.05 * 84 + 16.35 * 18 + 16.65 * 9}{14 + 25 + 84 + 18 + 9}$

$\bar x = \frac{2402.4}{150}$

$\bar x = 16.016$

The standard deviation is:

$\sigma = \sqrt{\frac{\sum(x_i - \bar x)^2}{\sum f}}$

$\sigma = \sqrt{\frac{(15.45 - 16.016)^2+ (15.75 - 16.016)^2+ (16.05 - 16.016)^2+ (16.35 - 16.016)^2+ (16.65 - 16.016)^2}{14 + 25 + 84 + 18 + 9}}$

$\sigma = \sqrt{\frac{0.90578}{150}}$

$\sigma = \sqrt{0.00603853333}$

$\sigma = 0.07770$

4 0

3 years ago

Write an equation of the circle with center (6, 2) and radius 4.

luda_lava [24]

Answer:

$(x-6)^2+(y-2)^2=16$ .

Step-by-step explanation:

$(x-h)^2+(y-k)^2=r^2$ is the equation for a circle with center (h,k) and radius r.

You are given center (6,2) and radius 4.

So we will replace h with 6 and k with 2 and r with 4.

This gives us:

$(x-6)^2+(y-2)^2=4^2$

Simplify:

$(x-6)^2+(y-2)^2=16$ .

8 0

3 years ago

Read 2 more answers