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umka2103 [35]
3 years ago
13

An object moves with a positive acceleration. Could the object be moving with increasing speed, decreasing speed or constant spe

ed
Physics
1 answer:
Masja [62]3 years ago
3 0

Answer:

Increasing speed.

Explanation:

In physics, acceleration can be defined as the rate of change of the velocity of an object with respect to time.

This simply means that, acceleration is given by the subtraction of initial velocity from the final velocity all over time.

Hence, if we subtract the initial velocity from the final velocity and divide that by the time, we can calculate an object’s acceleration.

Mathematically, acceleration is given by the equation;

Acceleration (a) = \frac{final \; velocity  -  initial \; velocity}{time}

In this scenario, an object moves with a positive acceleration. Thus, the object is moving with an increasing speed and as such it has acceleration in the same direction as its velocity with respect to time.

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photoshop1234 [79]

Answer:-2

Explanation:

7 0
2 years ago
Which of the following do not involve a direction?
Mazyrski [523]
I'm pretty sure the answer is D. The equation for acceleration is velocity divided by time. So the answer is D.
7 0
4 years ago
Lottery balls are thrown into a hopper and are set into motion by air forced through the container. each ball has a mass of 0.00
Marina CMI [18]
In this three body system total kinetic energy remains constant:
E_{k} = constant =0.0268 J

E_{k} = E_{k1}+ E_{k2}+ E_{k3}
If we assume that upwards movement is positive and downwards movement is negative the formula is:
E_{k} = E_{k1}- E_{k2}+ E_{k3}

Formula for kinetic energy is:
E_{k} = \frac{m v^{2} }{2}

Now we have:
E_{k} = \frac{m v_{1} ^{2} }{2} -\frac{m v_{2} ^{2} }{2} +\frac{m v_{3} ^{2} }{2} \\ E_{k} = \frac{m}{2} (v_{1} ^{2}-v_{2} ^{2}+v_{3} ^{2}) \\ \\ 0.0268= \frac{0.0044}{2} (1.3 ^{2}-1.66^{2}+v_{3} ^{2}) \\ \\ 0.0536=0.0022(1.69-2.7556+v_{3} ^{2}) \\ \\ v_{3} ^{2}=25.43 \\ \\ v_{3} =+-5.04

We got two solutions: positive and negative. The speed is 5.04 m/s and direction can be upwards and downwards.
3 0
3 years ago
An elevator is moving down with an acceleration of 3.36 m/s2.
sergeinik [125]

Answer : 413.44N

Here it is given that an elevator is moving down with an acceleration of 3.36 m/s² . And we are interested in finding out the apparent weight of a 64.2 kg man . For the diagram refer to the attachment .

  • From the elevator's frame ( non inertial frame of reference) , we would have to think of a pseudo force.
  • The direction of this force is opposite to the direction of acceleration the frame and its magnitude is equal to the product of mass of the concerned body with the acceleration of the frame .
  • When a elevator accelerates down , the weight recorded is less than the actual weight .

From the Free body diagram ,

\sf\longrightarrow Weight = mg - ma \\

\sf\longrightarrow Weight = m ( g - a ) \\

  • Mass of the man = 64.2 kg

\sf\longrightarrow Weight = 64.2( 9.8 - 3.36) N\\

\sf\longrightarrow Weight = 64.2 * 6.44 N\\

\sf\longrightarrow \underline{\boxed{\bf Weight_{apparent}= 413.44 N }} \\

5 0
2 years ago
What are five agents of erosion?
Minchanka [31]
Wind, running water, glaciers, waves, and gravity
4 0
3 years ago
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